Solve the equation15=2y-5

Find each probability if a die is rolled.<br> P(divisible by 4)

olga2289 [7]

When a die is rolled, there are six posible results:
1, 2, 3, 4, 5, and 6
Total number of posible results: n=6

Divisible by 4 is only the result 4
Number of favorable results: f=1

P(divisible by 4)=f/n
P(divisible by 4)=1/6
P(divisible by 4)=0.1667
P(divisible by 4)=0.1667*100%
P(divisible by 4)=16.67%

P(divisible by 4)=1/6=0.1667=16.67%

4 0

3 years ago

Please answer it for me too

djyliett [7]

Answer:

C

Step-by-step explanation:

I hope i got it correct :)

6 0

3 years ago

Read 2 more answers

Help me 1-6 with an explanation for a brainliest.

xxTIMURxx [149]

Answer:

Step-by-step explanation:

1. 5

2. -9

3. -4

4. 4 > .25

5. 0.142 < 7

6. -8 = -8

8 0

3 years ago

Use the distributive property to write an expression equivalent to 15(5+n)

Ratling [72]

The answer is i beleve 75+15n

8 0

3 years ago

Prove or disprove (from i=0 to n) sum([2i]^4) <= (4n)^4. If true use induction, else give the smallest value of n that it doe

ddd [48]

Answer:

The statement is true for every n between 0 and 77 and it is false for $n\geq 78$

Step-by-step explanation:

First, observe that, for n=0 and n=1 the statement is true:

For n=0: $\sum^{n}_{i=0} (2i)^4=0 \leq 0=(4n)^4$

For n=1: $\sum^{n}_{i=0} (2i)^4=16 \leq 256=(4n)^4$

From this point we will assume that $n\geq 2$

As we can see, $\sum^{n}_{i=0} (2i)^4=\sum^{n}_{i=0} 16i^4=16\sum^{n}_{i=0} i^4$ and $(4n)^4=256n^4$ . Then,

$\sum^{n}_{i=0} (2i)^4 \leq(4n)^4 \iff \sum^{n}_{i=0} i^4 \leq 16n^4$

Now, we will use the formula for the sum of the first 4th powers:

$\sum^{n}_{i=0} i^4=\frac{n^5}{5} +\frac{n^4}{2} +\frac{n^3}{3}-\frac{n}{30}=\frac{6n^5+15n^4+10n^3-n}{30}$

Therefore:

$\sum^{n}_{i=0} i^4 \leq 16n^4 \iff \frac{6n^5+15n^4+10n^3-n}{30} \leq 16n^4 \\\\ \iff 6n^5+10n^3-n \leq 465n^4 \iff 465n^4-6n^5-10n^3+n\geq 0$

and, because $n \geq 0$ ,

$465n^4-6n^5-10n^3+n\geq 0 \iff n(465n^3-6n^4-10n^2+1)\geq 0 \\\iff 465n^3-6n^4-10n^2+1\geq 0 \iff 465n^3-6n^4-10n^2\geq -1\\\iff n^2(465n-6n^2-10)\geq -1$