Evaluate the following expression:
1 answer:
You might be interested in
Lets check with every option
(a) [-4,-3]
We plug in -4 for x and -3 for x
f(-4) is positive and f(-3) is negative. there is some value at x=c on the interval [-4,-3] where f(c)=0. so there exists atleast one zero on this interval.
(b) [-3,-2]
We plug in -3 for x and -2 for x
f(-2) is negative and f(-3) is negative. there is no value at x=c on the interval [-3,-2] where f(c)=0.
(c) [-2,-1]
We plug in -2 for x and -1 for x
f(-2) is negative and f(-1) is positive. there is some value at x=c on the interval [-2,-1] where f(c)=0. so there exists atleast one zero on this interval.
(d) [-1,0]
We plug in -1 for x and 0 for x
f(-1) is positive and f(0) is negative. there is some value at x=c on the interval [-1,0] where f(c)=0. so there exists atleast one zero on this interval.
(e) [0,1]
We plug in 0 for x and 1 for x
f(0) is negative and f(1) is negative. there is no value at x=c on the interval [0,1] where f(c)=0.
(f) [1,2]
We plug in 1 for x and 2 for x
f(-4) is positive and f(-3) is negative. there is some value at x=c on the interval [-4,-3] where f(c)=0. so there exists atleast one zero on this interval.
so answers are (a) [-4,-3], (c) [-2,-1], (d) [-1,0], (f) [1,2]
Remember to use SOH CAH TOA. Very simple. I ended up getting 18/17 as my answer
Answer:
Step-by-step explanation:
Given:
- AB = x + 4
- BC = 2x – 10
- AC = 2x + 1
We can illustrate this relationship as:
(2x + 1)
___↑___
| |
A — B — C
|____|___|
↓ ↓
(x + 4) (2x – 10)
_______________________________
When you are given an algebraic expression for the length of a segment, you can solve for that value by knowing that the sum of two segments AB + BC = AC.
Thus:
(x + 4) + (2x – 10) = (2x + 1)
[Regroup terms]
(x + 2x) + (4 – 10) = (2x + 1)
[Simplify]
(3x – 6) = (2x + 1)
[subtract 2x from both sides to isolate the variable]
(3x – 6) – 2x = (2x + 1) – 2x
[Regroup terms]
(3x – 2x) – 6 = (2x – 2x) + 1
x – 6 = 1
[Add 6 to both sides to isolate the constant]
x – 6 + 6 = 1 + 6
[Simplify]
x = 7