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Andrews [41]
3 years ago
5

You can add ________ without changing either fraction's denominator.

Mathematics
2 answers:
horrorfan [7]3 years ago
6 0

Answer:

D I believe (so 2/5 and 3/5)

PolarNik [594]3 years ago
4 0

Answer:

D

Step-by-step explanation:

Because D has same dominator and you don’t change dominator when adding fractions

Hope this helps.

Mark brainliest if it help.

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3. If the circumference of a round table is 90 inches, what is the area of the table to the nearest
Katen [24]
It would be 7193 because I did the test. Thank you
6 0
2 years ago
What is the simplest form of the expression?
Rina8888 [55]
^ 3 sqrt 750 + ^ 3 sqrt 2058 - ^ 3 sqrt 48
 Rewriting the expression we have
 ^ 3 sqrt (6 * x ^ 3) + ^ 3 sqrt (6 * y ^ 3) - ^ 3 sqrt (6 * z ^ 3)
 That is, we have the following equations:
 6 * x ^ 3 = 750
 6 * y ^ 3 = 2058
 6 * z ^ 3 = 48
 Clearing x, y and z we have:
 x = 5
 y = 7
 z = 2
 Then, rewriting the expression
 x (^ 3 sqrt (6)) + y (^ 3 sqrt (6)) - z (^ 3 sqrt (6))
 Substituting the values
 5 (^ 3 sqrt (6)) + 7 (^ 3 sqrt (6 *)) - 2 (^ 3 sqrt (6))
 10 (^ 3 sqrt (6))
 answer
 the simple form of the expression is
 D) 10 ^ 3 sqrt 6
3 0
3 years ago
2 + 4x - 4 = 0 which gives x =
ExtremeBDS [4]

Answer:

x =  \frac{1}{2}

Step-by-step explanation:

2 + 4x - 4 = 0 \\ 2 + 4x = 0 + 4 \\ 2 + 4x = 4 \\ 4x = 4 - 2 \\ 4x = 2 \\  \frac{4x}{4}  =  \frac{2}{4}  \\ x =  \frac{1}{2}

7 0
3 years ago
Read 2 more answers
If a fire is burning a building and it takes 2 hours to put it out using 2000 gal./min., what minimum diameter cylindrical tank
strojnjashka [21]

Answer:

The minimum diameter of the cylindrical tank needed to store the quantity needed to put out the fire is approximately 58.415 feet.

Step-by-step explanation:

A gallon equals 0.134 cubic feet. First, we determine the amount of water (Q), measured in cubic feet, needed to put out the fire under the assumption that water is consumed at constant rate:

Q = \dot Q \cdot \Delta t (1)

Where:

\dot Q - Volume rate, measured in feet per minute.

\Delta t - Time, measured in minutes.

If we know that \dot Q = 2000\,\frac{gal}{min} and \Delta t = 120\,min, then the amount of water is:

Q = \left(2000\,\frac{gal}{min} \right)\cdot (120\,min) \cdot \left(0.134\,\frac{ft^{3}}{gal} \right)

Q = 32160\,ft^{3}

And the diameter of the cylindrical tank based on the capacity found above is determined by volume formula for a cylinder:

Q = \frac{\pi}{4}\cdot D^{2}\cdot h (2)

Where:

D - Diameter, measured in feet.

h - Height, measured in feet.

If we know that Q = 32160\,ft^{3} and h = 12\,ft, then the minimum diameter is:

D^{2} = \frac{4\cdot Q}{\pi\cdot h}

D = 2\cdot \sqrt{\frac{Q}{\pi\cdot h} }

D = 2\cdot \sqrt{\frac{32160\,ft^{3}}{\pi\cdot (12\,ft)} }

D \approx 58.415\,ft

The minimum diameter of the cylindrical tank needed to store the quantity needed to put out the fire is approximately 58.415 feet.

8 0
2 years ago
I need help plsss, check all that apply
Natalka [10]
They lie in the same plane is the answer ;)
4 0
3 years ago
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