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irga5000 [103]
3 years ago
10

Multiple choice math question, need some help please, thanks

Mathematics
1 answer:
enot [183]3 years ago
6 0
20,000 miles because 1 mile and 1,000 miles are too small and 100,000 is too big. Hope that this helped!
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Lydia ran 10 miles in 120 minutes. How many minutes did she run per mile?
Digiron [165]

Answer:

It took Lydia 12 minutes to run each mile

Step-by-step explanation:

120/10

6 0
3 years ago
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What is the value of "c" in the quadratic equation 3x 2 + 5x + 7 = 0? 3 5 7
Maslowich

Answer:

7

Step-by-step explanation:

The standard form of a quadratic equation is

y = ax² + bx + c     where a ≠ 1

c is the number without a variable

5 0
3 years ago
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1. {(1, -2), (-2, 0), (-1, 2), (1, 3)}<br> Function:<br> Domain:<br> Range:
Anit [1.1K]

Answer: not a function; domain-2,-1,1 ; range-2,0,2,3

Step-by-step explanation:

3 0
3 years ago
a conical paper cup is hold 1/4 of a liter . find height and radius of cone which minimizes the amount of paper needed to make t
ASHA 777 [7]

Answer:

h ≈ 7.816 cm

r ≈ 5.527 cm

Step-by-step explanation:

The volume of a cone is:

V = ⅓ π r² h

The lateral surface area of a cone is:

A = π r √(r² + h²)

1/4 of a liter is 250 cm³.

250 = ⅓ π r² h

h = 750 / (π r²)

Square both sides of the area equation:

A² = π² r² (r² + h²)

Substitute for h:

A² = π² r² (r² + (750 / (π r²))²)

A² = π² r² (r² + 750² / (π² r⁴))

A² = π² (r⁴ + 750² / (π² r²))

Take derivative of both sides with respect to r:

2A dA/dr = π² (4r³ − 2 × 750² / (π² r³))

Set dA/dr to 0 and solve for r.

0 = π² (4r³ − 2 × 750² / (π² r³))

0 = 4r³ − 2 × 750² / (π² r³)

4r³ = 2 × 750² / (π² r³)

r⁶ = 750² / (2π²)

r³ = 750 / (π√2)

r³ = 375√2 / π

r = ∛(375√2 / π)

r ≈ 5.527

Now solve for h.

h = 750 / (π r²)

h = 750 / (π (375√2 / π)^⅔)

h = 750 ∛(375√2 / π) / (π (375√2 / π))

h = 2 ∛(375√2 / π) / √2

h = √2 ∛(375√2 / π)

h ≈ 7.816

Notice that at the minimum area, h = r√2.

6 0
3 years ago
Pls help <br> And explain how you got your answer
frosja888 [35]

2000x5x400÷100=40000

8 0
3 years ago
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