Graph B has a slope of -3 and a y-intercept of -5, therefore, the best graph that represents the equation is: Graph B.
<h3>How to Identify the Graph of the Equation of a Line?</h3>
The equation of a line can be rewritten in slope-intercept form as, y = mx + b.
The graph that represents the equation of the line, would have a slope of m and a y-intercept of b.
Given the equation:
3x + y = -5
Rewrite in slope-intercept form:
y = -3x - 5
The slope of the graph, would be m = -3, and the y-intercept would b b = -5.
Thus, graph B has a slope of -3 and a y-intercept of -5, therefore, the best graph that represents the equation is: Graph B.
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Answer:
x³+3x²+4x+12
Step-by-step explanation:
you are going to write both equations and distribute. if there are like terms, combine them and then put it order.
(x + 3) × (x² + 4)
x³ + 4x + 3x² + 12
when putting in order, you want the highest power to the left and then the lowest power to the right.
so
x³+3x²+4x+12
The discontinuity occurs at x = 0, since that is the only "problem" place in the graph that makes the function undefined. A vertical asymptote exists there. It is nonremoveable.
Answer:
c
Step-by-step explanation
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Answer:
r = 64
Step-by-step explanation:
r = (k*t*u)/s
Where,
k = constant of proportionality
t = -12,
u= -7,
s= -4,
r= -126.
r = (k*t*u)/s
-126 = (k*-12*-7)/-4
-126 * -4 = 84k
504 = 84k
k = 504/84
k = 6
Find r when t= -8, u= 8, and s= -6.
r = (k*t*u)/s
= (6*-8*8) / -6
= -384 / -6
= 64
r = 64