Answer:
sdf
Step-by-step explanation:
sdfgh
The area of an equilateral triangle of side "s" is s^2*sqrt(3)/4. So the volume of the slices in your problem is
(x - x^2)^2 * sqrt(3)/4.
Integrating from x = 0 to x = 1, we have
[(1/3)x^3 - (1/2)x^4 + (1/5)x^5]*sqrt(3)/4
= (1/30)*sqrt(3)/4 = sqrt(3)/120 = about 0.0144.
Since this seems quite small, it makes sense to ask what the base area might be...integral from 0 to 1 of (x - x^2) dx = (1/2) - (1/3) = 1/6. Yes, OK, the max height of the triangles occurs where x - x^2 = 1/4, and most of the triangles are quite a bit shorter...
Answer:
The price of an adult ticket it $5
Step-by-step explanation:
To solve this, we would find the system of equations. We would set up two equations that will represent the situation.
Let c = price per children ticket
Let a = price per adult ticket
Santo:
5c + 1a = 16.25
Hulda:
4c + 3a = 24
5c + 1a = 16.25 -> a = 16.25 - 5c
4c + 3a = 24
4c + 3(16.25 - 5c) = 24
4c + 48.75 - 15c = 24
-11c + 48.75 = 24
-48.75 -48.75
-11c = -24.75
/-11 /-11
c = 2.25
5c + a = 16.25
5(2.25) + a = 16.25
11.25 + a = 16.25
-11.25 -11.25
a = 5
a = $5 , c = $2.25
Answer:
(x-6)^2+(y-14)^2=4
Step-by-step explanation:
