What is the value of fraction 1 over 3x2 + 5.2y when x = 3 and y = 2?

2 answers:

4 0

$\dfrac{1}{3}x^2+5.2y\\\\for\ x=3\ and\ y=2\\\\\dfrac{1}{3}\cdot3^2+5.2\cdot2=\dfrac{1}{3}\cdot9+10.4=\dfrac{9}{3}+10.4=3+10.4=13.4$

GrogVix [38]2 years ago

3 0

Answer:

B. 13.4

Step-by-step explanation:

We have the fraction, $L=\frac{1}{3}x^2+5.2y$ .

It is required to find the value of the fraction when x = 3 and y = 2.

So, on substituting these values, we get,

$L=\frac{1}{3}(3)^2+5.2\times 2$

i.e. $L=\frac{9}{3}+10.4$

i.e. $L=3+10.4$

i.e. $L=13.4$

So, the value of the fraction is 13.4

Hence, option B is correct.

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Please no wrong answers <br>what to do next??

Finger [1]

Step-by-step explanation:

I am not sure what you want to calculate as ultimate goal.

but your have an error already in your third line in the picture.

(3-6i)(2-4i) = 3×(2-4i) - 6i(2-4i)

you had there a "+" instead of a "-".

and then you made subsequent mistakes in every line, some of them are funnily bringing you more back to the real result (e.g. -12i + 12i would be 0 and not -24i, but if the third line would have been correct, then yes, -24i is actually needed) - but not completely.

= 3×2 - 3×4i - 6i×2 + 6i×4i =

= 6 - 12i - 12i + 24×-1 = 6 - 24i - 24 = -24i - 18

then in the last 3 lines you kind of lose it completely. I am absolutely not sure, what you are calculating, and where the "+" cube from instead of "×" (multiplications) and such.

(3+6i)(2+4i) = 3×2 + 3×4i + 6i×2 + 6i×4i =

= 6 + 12i + 12i + 24×-1 =

= 6 + 24i - 24 = 24i - 18

is that what you wanted to show ?

7 0

2 years ago

A math class is having a discussion on how to determine if the expressions 4 x minus x + 5 and 8 minus 3 x minus 3 are equivalen

dedylja [7]

Answer:

They are NOT equivalent

Step-by-step explanation:

4x-x+5 and 8-3x-3