Question

What is the value of fraction 1 over 3x2 + 5.2y when x = 3 and y = 2?

Answer 1

$\dfrac{1}{3}x^2+5.2y\\\\for\ x=3\ and\ y=2\\\\\dfrac{1}{3}\cdot3^2+5.2\cdot2=\dfrac{1}{3}\cdot9+10.4=\dfrac{9}{3}+10.4=3+10.4=13.4$

Answer 2

Answer:

B. 13.4

Step-by-step explanation:

We have the fraction, $L=\frac{1}{3}x^2+5.2y$.

It is required to find the value of the fraction when x = 3 and y = 2.

So, on substituting these values, we get,

$L=\frac{1}{3}(3)^2+5.2\times 2$

i.e. $L=\frac{9}{3}+10.4$

i.e. $L=3+10.4$

i.e. $L=13.4$

So, the value of the fraction is 13.4

Hence, option B is correct.