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Kobotan [32]
2 years ago
8

50 points to answer this for me

Mathematics
2 answers:
Stolb23 [73]2 years ago
7 0
The correct question is
Part A: Explain why the x-coordinates of the points where the graphs of the equations y = 4−x and y = 8-x^-1 intersect are the solutions of the equation 4−x = 8-x^-1<span>.
Part B: Make tables to find the solution to 4−x = </span>8-x^-1<span>. Take the integer values of x between −3 and 3. 
Part C: How can you solve the equation 4−x = </span>8-x^-1 graphically?

Part A.  We have two equations:  y = 4-x   and   y = 8-x^-1
Given two simultaneous equations that are both to be true, then the solution is the points where the lines cross. The intersection is where the two equations are equal. Therefore the solution that works for both equations is when
4-x = 8-x^-1
This is where the two graphs will cross and that is the common point that satisfies both equations.

Part B
see the attached table
the table shows that one of the solutions is in the interval [-1,1]

Part C To solve graphically the equation 4-x = 8-x^-1

We would graph both equations: y = 4-x  and   y = 8-x^-1

The point on the graph where the lines cross is the solution to the system of equations.

using a graph tool

see the attached figure N 2

the solutions are the points

(-4.24,8.24)

(0.24,3.76)




Marizza181 [45]2 years ago
7 0

Part A.  We have two equations:  y = 4-x   and   y = 8-x^-1

Given two simultaneous equations that are both to be true, then the solution is the points where the lines cross. The intersection is where the two equations are equal. Therefore the solution that works for both equations is when

4-x = 8-x^-1

This is where the two graphs will cross and that is the common point that satisfies both equations.

Part B

see the attached table

the table shows that one of the solutions is in the interval [-1,1]

Part C To solve graphically the equation 4-x = 8-x^-1

We would graph both equations: y = 4-x  and   y = 8-x^-1

The point on the graph where the lines cross is the solution to the system of equations.

using a graph tool

see the attached figure N 2

the solutions are the points

(-4.24,8.24) (0.24,3.76)

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Suppose that the researchers wanted to estimate the mean reaction time to within 6 msec with 95% confidence. Using the sample st
Lisa [10]

Answer:

a) The 95% confidence interval would be given by (509.592;550.308)  

b) n=523 rounded up to the nearest integer  

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

\bar X=530 represent the sample mean for the sample  

\mu population mean

s=70 represent the sample standard deviation  

n=48 represent the sample size (variable of interest)  

Confidence =95% or 0.995

Part a

The confidence interval for the mean is given by the following formula:  

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}} (1)  

The degrees of freedom are df=n-1=48-1=47

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,47)".And we see that z_{\alpha/2}=2.01  

Now we have everything in order to replace into formula (1):  

530-2.01\frac{70}{\sqrt{48}}=509.692  

530+2.01\frac{70}{\sqrt{48}}=550.308  

So on this case the 95% confidence interval would be given by (509.592;550.308)  

Part b

The margin of error is given by this formula:  

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (a)  

Assuming that \hat \sigma =s

And on this case we have that ME =6msec, and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=(\frac{z_{\alpha/2} \sigma}{ME})^2 (b)  

The critical value for 95% of confidence interval is provided, z_{\alpha/2}=1.96, replacing into formula (b) we got:  

n=(\frac{1.96(70)}{6})^2 =522.88 \approx 523  

So the answer for this case would be n=523 rounded up to the nearest integer  

3 0
2 years ago
Please help me with this questions I need the answer
Anastaziya [24]

Answer:

it rly doesnt matter

Step-by-step explanation:

try making _/

u can see that u can have 2 angles that you can make. Doesnt matter! :)

5 0
3 years ago
Read 2 more answers
A photo is 4 inches wide. It is placed inside a frame with a border that is x inches wide. The total width of the photo and the
Anna [14]
4 + 2x = 7
2x = 7 - 4 = 3
x = 3/2 = 1.5 inches
5 0
3 years ago
:
valkas [14]

Answer:

20 home runs left to hit.

Step-by-step explanation:

Ok so 100%/20% is 5. Increment 5 home runs until you get to 100%. So, 20% =5, 40% = 10, 80% = 15, and 100% = 20

7 0
2 years ago
Read 2 more answers
What is x + 5 equals 10
Wittaler [7]

x+5= 10

move +5 to the other side

sign changes from +5 to -5

x+5-5= 10-5

x= 10-5

x= 5

Answer:

x= 5

7 0
3 years ago
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