Answer:
The expected net winnings for the bet are -$1.0526
Step-by-step explanation:
P(x =+$20) = P(Black outcome) = 18/38
P(x =-$20) = P(red outcome) + P(green outcome)
= 18/38 + 2/38 = 20/38
Hence the probability distribution of x = $20 , P(x) = 18/38
x = -$20, P(x) = 20/38
Expected value of the random variable x is given by ;
miu = Summation [xP(x)] = 20(18/38) - 20( 20/38)
= -$1.0526
hence, the expected net winnings for the bet are -$1.0526
This implies that if a player bet on a very large number of games, the player would on the average lose $1.0526 per single bet
Answers: 0.286
Explanation:
Let E → major in Engineering
Let S → Play club sports
P (E) = 28% = 0.28
P (S) = 18% = 0.18
P (E ∩ S ) = 8% = 0.08
Probability of student plays club sports given majoring in engineering,
P ( S | E ) = P (E ∩ S ) ÷ P (E) = 0.08 ÷ 0.28 = 0.286
Answer:
Subtract 9 from both sides of the equation.
I believe the answer is true
