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QveST [7]
3 years ago
11

What is the difference? StartFraction 2 x + 5 Over x squared minus 3 x EndFraction minus StartFraction 3 x + 5 Over x cubed minu

s 9 x EndFraction minus StartFraction x + 1 Over x squared minus 9 EndFraction StartFraction (x + 5) (x + 2) Over x cubed minus 9 x EndFraction StartFraction (x + 5) (x + 4) Over x cubed minus 9 x EndFraction StartFraction negative 2 x + 11 Over x cubed minus 12 x minus 9 EndFraction StartFraction 3 (x + 2) Over x squared minus 3 x EndFraction

Mathematics
2 answers:
Sunny_sXe [5.5K]3 years ago
6 0

Answer:

<h2>\frac{(x + 5)(x + 2)}{ {x}^{3} - 9x }</h2>

First option is the correct option.

Step-by-step explanation:

\frac{2x + 5}{ {x}^{2} - 3x }  -  \frac{3x + 5}{ {x}^{3} - 9x }  -  \frac{x + 1}{ {x}^{2} - 9 }

Factor out X from the expression

\frac{2x + 5}{x(x - 3)}  -  \frac{3x + 5}{x( {x}^{2}  - 9)}  -  \frac{x + 1}{ {x}^{2}  - 9}

Using {a}^{2}  -  {b}^{2}  = (a - b)(a + b) , factor the expression

\frac{2x + 5}{x(x - 3)}  -  \frac{3x + 5}{x(x - 3)(x + 3) }  -  \frac{x + 1}{(x - 3)(x + 3)}

Write all numerators above the Least Common Denominators x ( x - 3 ) ( x + 3 )

\frac{(x + 3) \times (2x - 5) - (3x + 5) - x \times (x + 1)}{x(x - 3)(x + 3)}

Multiply the parentheses

\frac{2 {x}^{2}  + 5x + 6x + 15 - (3x + 5) - x(x + 1)}{x(x - 3)(x + 3)}

When there is a (-) in front of an expression in parentheses, change the sign of each term in the expression

\frac{2 {x}^{2}  + 5x + 6x + 15 - 3x - 5 - x \times (x + 1)}{x(x - 3)(x + 3)}

Distribute -x through the parentheses

\frac{2 {x}^{2}  + 5x + 6x + 15 - 3x - 5 -  {x}^{2} - x }{x(x - 3)(x + 3)}

Using {a}^{2}  -  {b}^{2}  = (a + b)(a - b) , simplify the product

\frac{2 {x}^{2}  + 5x + 6x + 15 - 3x - 5 -  {x}^{2}  - x}{x( {x}^{2}  - 9)}

Collect like terms

\frac{ {x}^{2}  + 7x + 15 - 5}{x( {x}^{2}  - 9)}

Subtract the numbers

\frac{ {x}^{2}  + 7x + 10}{ x({x}^{2}   - 9)}

Distribute x through the parentheses

\frac{ {x}^{2}  + 7x + 10}{ {x}^{3}  - 9x}

Write 7x as a sum

\frac{ {x}^{2} + 5x +2x + 10 }{ {x}^{3} - 9x }

Factor out X from the expression

\frac{x(x + 5) + 2x + 10}{ {x}^{3}  - 9x}

Factor out 2 from the expression

\frac{x( x + 5) + 2(x + 5)}{ {x}^{3} - 9x }

Factor out x + 5 from the expression

\frac{(x + 5)(x + 2)}{ {x}^{3} - 9x }

Hope this helps...

Best regards!!

Alex787 [66]3 years ago
3 0

Answer: The Answer is A

Step-by-step explanation: EDGE 2020

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Answer:

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Step-by-step explanation:

Given equation: \frac{3}{4}y + \frac{1}{2} = 3 \frac{1}{4}

In the given equation, \frac{3}{4} is a coefficient and y is the variable.

coefficient is a constant number or quantity multiplied to a variable in an algebric expression. Like in the above equation \frac{3}{4} is a coefficient and y is the variable. We use term variable for y as its value may vary or change. If variable does not have any coefficient in any expression then in that case, we consider 1 as coefficient, for example: x+4, here variable have 1 as coefficient.

Hence, the fractional coefficient is \frac{3}{4}.

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The perimeter of this figure Is 42.5<br><br>Find the area of the figure.​
Murljashka [212]

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<h3>How to explain the volume?</h3>

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You would want to have the highest possible volume to surface area ratio in an ice cube. If your ice cube is mostly surface area with less volume, it will melt quickly and water down your drink. If your ice cube has a higher ratio of volume to the surface area, it will stay solid longer and chill your drink longer.

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