Let the required point be (a,b)
The distance of (a,b) from (7,-2) is
= 
But this distance needs to be betweem 50 & 60
So
Squaring all sides
2500 < (a-7)² + (b+2)² < 3600
Let a = 7
So we have
2500 < (b+2)² <3600
b+2 < 60 or b+2 > -60 => b <58 or b > -62
Also
b+2 >50 or b + 2 < -50 => b >48 or B < -52
Let us take one value of b < 58 say b = 50
So now we have the point as (7, 50)
The other point is (7,-2)
Distance between them
= 
This is between 50 & 60
Hence one point which has a distance between 50 & 60 from the point (7,-2) is (7, 50)
yo sup??
mid point of circle=centre of circle
let centre be O(3,2)
and the point be P(-4,8) and the other point be Q(x,y)
by mid point formula
-4+x/2=3 and 8+y/2=2
x=10 and y=-4
therefore coordinates of the other point are (10,-4)
Hope this helps.
1) 108
2) 72
3) 36
4) 72
5) 72
6) 144
7) 72
8) 72
9) 108
10) 108
I hope this helped
Answer:
see below
Step-by-step explanation:
Pedro has 3 boxes of 6 markers.
3*6 = 18 markers
We can divide this by 2 because this is even
18/2 = 9
There are 9 in each group
Rafael has 5 boxes of 5 markers
5*5 = 25
We cannot divide this by 2 because this is odd
