The fact that it's a renewable resource would be the only benefit. All of the others are disadvantages
The magnitude of the work done by the electric field of the membrane is <u>W = 1.28 × 10⁻²⁰ Joules</u>.
We start with the necessity to take into account a value for the voltage present there in order to solve this problem by first considering that the membranes have two layers, one internal and one external, each responsible for producing a potential difference between the two levels.
As a result, in order to find a solution, it is necessary to take into account the potential difference between the two surfaces. In this instance, we'll assume a particular value for the load, but the recipient is free to substitute a different value if they prefer.
The product of the potential difference and the charge is used to define the work that an electric field performs. The charge of the potassium ion will be equal to that of its electron, so,
q = 1.6 × 10⁻¹⁹ Coulombs
Then the Work would be:
W = Vq
Here,
v = Potential difference
q = Charge
The 80mV potential difference we will have is quantified as follows:
W = (80mV (1V/1000mV))( 1.6 × 10⁻¹⁹ C)
W = 1.28 × 10⁻²⁰ Joules is the amount of work that the membrane's electric field has produced.
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Answer:
<h2>
potassium</h2>
Explanation:
The heartbeats of the heart are controlled by the sinoatrial node also known as the pacemaker of the heart. The impulse is generated in the conducting cells of the pacemaker as a result of the movement of sodium, potassium and calcium ions.
The sodium channels allow the movement of sodium into the cell which depolarizes the membrane from -60mv to -40 mv. At this point, the calcium gated channels open which allow the entry of the calcium in the cell which depolarizes the cell up to +5mv.
At this point, the potassium channels open which allows the potassium ions to move out of the cell. This repolarizes the cell and hence the cycle again begins. Reducing the permeability of the potassium ions help generate the autorhythmicity due to repolarization and thus is the correct answer.
