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4 years ago

What is the answer of -10(-5)

Mathematics

2 answers:

navik [9.2K]4 years ago

5 0

The answer is 50
(-10)(-5)

Aliun [14]4 years ago

5 0

A negative times another negative equals a positive so, -10(-5)= 50

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Please help me guys I beg you I will give you lots of credit plz

IRINA_888 [86]

Answer:

11m/min

Step-by-step explanation:

slope of the line = velocity of the turtle

slope = y/x

= 55/5

=11

4 0

3 years ago

Read 2 more answers

The sum of two numbers is 35.

LUCKY_DIMON [66]

Answer:

Larger number(x)=20

Step-by-step explanation:

They're saying that the larger number 3 times is EQUAL(the same) to 4 times the smaller number.

The smallest number=35-x.

The larger number= x.

3 times the larger number=3x

4 times the smaller number=4(35-x)

Now, input it into an equation and solve:

3x=4(35-x) Distribute by multiplying 4 with 35 and x.

3x+4x=140-4x+4x Get 140 by itself by adding 4x.

7x/7=140/7 Divide.

x=20

Since x= the larger number, x=20.

8 0

4 years ago

What is a solution to the equation 3 / m + 3 - M / 3 - M equals m^2 + 9 / m^2-9?

Mnenie [13.5K]

Answer: Last option.

Step-by-step explanation:

Given the equation:

$\frac{3}{m+3}-\frac{m}{3-m}=\frac{m^2+9}{m^2-9}$

Follow these steps to solve it:

- Subtract the fractions on the left side of the equation:

$\frac{3(3-m)-m(m+3)}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{9-3m-m^2-3m}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}$

- Using the Difference of squares formula ( $a^2-b^2=(a+b)(a-b)$ ) we can simplify the denominator of the right side of the equation:

$\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{(m+3)(m-3)}$

- Multiply both sides of the equation by $(m+3)(3-m)$ and simplify:

$\frac{(-m^2-6m+9)(m+3)(3-m)}{(m+3)(3-m)}=\frac{(m^2+9)(m+3)(3-m)}{(m+3)(m-3)}\\\\-m^2-6m+9=\frac{(m^2+9)(3-m)}{(m-3)}$

- Multiply both sides by $m-3$ :

$(-m^2-6m+9)(m-3)=\frac{(m^2+9)(3-m)(m-3)}{(m-3)}\\\\(-m^2-6m+9)(m-3)=(m^2+9)(3-m)$

- Apply Distributive property and simplify:

$(-m^2-6m+9)(m-3)=(m^2+9)(3-m)\\\\-m^3-6m^2+9m+3m^2+18m-27=3m^2+27-m^3-9m\\\\-m^3-3m^2+27m-27+m^3-3m^2+9m-27=0\\\\-6m^2+36m-54=0$

- Divide both sides of the equation by -6:

$\frac{-6m^2+36m-54}{-6}=\frac{0}{-6}\\\\m^2-6m+9=0$

- Factor the equation and solve for "m":

$(m-3)^2=0\\\\m=3$

In order to verify it, you must substitute $m=3$ into the equation and solve it:

$\frac{3}{3+3}-\frac{3}{3-3}=\frac{3^2+9}{3^2-9}\\\\\frac{3}{6}-\frac{3}{0}=\frac{18}{0}$

<em>NO SOLUTION</em>

7 0

3 years ago

Steven spent 2 hours and 30 minutes to attend 3 classes. If it took him the same amount of time to attend each class, how long w

gtnhenbr [62]

If you break down the beginning part, its 150 ÷ 3 = 50, so that means each class took 50 minutes. Not only that, you get your 'Time/Minutes per Class'. From there, you can multiply 50 by 5 and get 250 minutes, or 4 hours and 10 minutes.

In short: 250 minutes or 4 hours and 10 minutes.

7 0

3 years ago

What are the next two terms after 1, 4, 6, 24, 26

levacccp [35]

108, and 110 because the pattern is multiply by 4, then add 2

6 0

3 years ago