1/4, 8/15, 6/5
One way to figure this out is to divide the fractions and find which number is bigger
Or you should know 1/4= .25 , 8/15 is around half or .5 and 6/5 the numerator is larger than the denominator, so it would be bigger than 1 <span />
Answer:
m∠WZX = 41°
Step-by-step explanation:
diagonals bisect angles and opposite angles are congruent
therefore, ∠WXY ≅ ∠WZY
∠WZY must equal [360 - 2(68)] ÷ 2 which equals 112°
If ∠WXZ = 71° then so does ∠XZY
Which means that ∠WZX must equal 112-71 which is 41°

now, by traditional method, as "x" progresses towards the positive infinitity, it becomes 100, 10000, 10000000, 1000000000 and so on, and notice, the limit of the numerator becomes large.
BUT, notice the denominator, for the same values of "x", the denominator becomes larg"er" than the numerator on every iteration, ever becoming larger and larger, and yielding a fraction whose denominator is larger than the numerator.
as the denominator increases faster, since as the lingo goes, "reaches the limit faster than the numerator", the fraction becomes ever smaller an smaller ever going towards 0.
now, we could just use L'Hopital rule to check on that.

notice those derivatives atop and bottom, the top is static, whilst the bottom is racing away to infinity, ever going towards 0.
Answer: The required solution is 
Step-by-step explanation:
We are given to solve the following differential equation :

where k is a constant and the equation satisfies the conditions y(0) = 50, y(5) = 100.
From equation (i), we have

Integrating both sides, we get
![\int\dfrac{dy}{y}=\int kdt\\\\\Rightarrow \log y=kt+c~~~~~~[\textup{c is a constant of integration}]\\\\\Rightarrow y=e^{kt+c}\\\\\Rightarrow y=ae^{kt}~~~~[\textup{where }a=e^c\textup{ is another constant}]](https://tex.z-dn.net/?f=%5Cint%5Cdfrac%7Bdy%7D%7By%7D%3D%5Cint%20kdt%5C%5C%5C%5C%5CRightarrow%20%5Clog%20y%3Dkt%2Bc~~~~~~%5B%5Ctextup%7Bc%20is%20a%20constant%20of%20integration%7D%5D%5C%5C%5C%5C%5CRightarrow%20y%3De%5E%7Bkt%2Bc%7D%5C%5C%5C%5C%5CRightarrow%20y%3Dae%5E%7Bkt%7D~~~~%5B%5Ctextup%7Bwhere%20%7Da%3De%5Ec%5Ctextup%7B%20is%20another%20constant%7D%5D)
Also, the conditions are

and

Thus, the required solution is 
Answer:
SRT
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