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Ray Of Light [21]
3 years ago
12

The greatest amount of rainfall is times as great as the least amount of rainfall

Mathematics
2 answers:
navik [9.2K]3 years ago
5 0

Answer:

16 times

Step-by-step explanation:

The question is basically asking :

<em>what number multiplied with the least amount would give me the greatest amount??</em>

<em />

<em>Let that number be x, so we can say:</em>

<em>least amount * x = greatest amount</em>

<em />

From the plot, we can see that least amount is 1/8 inches

The greatest amount is 2 inches

Now we can put it into the formula and find x:

1/8 * x = 2

x = 2/(1/8)

x = 16

Makovka662 [10]3 years ago
4 0

Answer:

16 times

Step-by-step explanation:

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Answer:

D) 0 ≤ p ≤ 1

Probability is 0 when there's no chance of occurrence

Probability is 1 when the event is certain to happen

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Answer:

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Step-by-step explanation:

The sum of all the degrees in a triangle is 180. First, you have to rind what the third degree of the triangle is. We will call this y.

85+90+y=180

175+y=180

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The floor is flat, so it will be 180 degrees, therefore, x+y=180. We can substitute 5 in for y, so 5+x=180.

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Nostrana [21]

Answer:

\displaystyle   \begin{cases} \displaystyle  {x} _{1} =  - p \\   \displaystyle x _{2}   =  -  q \end{cases}

Step-by-step explanation:

we would like to solve the following equation for x:

\displaystyle  \frac{1}{p}  +  \frac{1}{q}  +  \frac{1}{x}  =  \frac{1}{p  + q + x}

to do so isolate \frac{1}{x} to right hand side and change its sign which yields:

\displaystyle  \frac{1}{p}  +  \frac{1}{q}    =  \frac{1}{p  + q + x}  -  \frac{1}{x}

simplify Substraction:

\displaystyle  \frac{1}{p}  +  \frac{1}{q}    =  \frac{x - (q + p +  x)}{x(p  + q + x)}

get rid of only x:

\displaystyle  \frac{1}{p}  +  \frac{1}{q}    =  \frac{  - (q + p )}{x(p  + q + x)}

simplify addition of the left hand side:

\displaystyle  \frac{q + p}{pq}     =  \frac{  - (q + p )}{x(p  + q + x)}

divide both sides by q+p Which yields:

\displaystyle  \frac{1}{pq}     =  \frac{  -1}{x(p  + q + x)}

cross multiplication:

\displaystyle    x(p  + q + x)  =   - pq

distribute:

\displaystyle    xp  + xq +  {x}^{2} =   - pq

isolate -pq to the left hand side and change its sign:

\displaystyle    xp  + xq +  {x}^{2} + pq =  0

rearrange it to standard form:

\displaystyle   {x}^{2} +    xp  + xq  + pq =  0

now notice we end up with a <u>quadratic</u><u> equation</u> therefore to solve so we can consider <u>factoring</u><u> </u><u>method</u><u> </u><u> </u>to use so

factor out x:

\displaystyle  x( {x}^{} +   p ) + xq  + pq =  0

factor out q:

\displaystyle  x( {x}^{} +   p ) +q (x + p)=  0

group:

\displaystyle  ( {x}^{} +   p ) (x + q)=  0

by <em>Zero</em><em> product</em><em> </em><em>property</em> we obtain:

\displaystyle   \begin{cases} \displaystyle  {x}^{} +   p  = 0 \\   \displaystyle x + q=  0 \end{cases}

cancel out p from the first equation and q from the second equation which yields:

\displaystyle   \begin{cases} \displaystyle  {x}^{}   =  - p \\   \displaystyle x  =  -  q \end{cases}

and we are done!

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Answer:

Diagram for success. ...

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Step-by-step explanation:

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