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Ray Of Light [21]
3 years ago
12

The greatest amount of rainfall is times as great as the least amount of rainfall

Mathematics
2 answers:
navik [9.2K]3 years ago
5 0

Answer:

16 times

Step-by-step explanation:

The question is basically asking :

<em>what number multiplied with the least amount would give me the greatest amount??</em>

<em />

<em>Let that number be x, so we can say:</em>

<em>least amount * x = greatest amount</em>

<em />

From the plot, we can see that least amount is 1/8 inches

The greatest amount is 2 inches

Now we can put it into the formula and find x:

1/8 * x = 2

x = 2/(1/8)

x = 16

Makovka662 [10]3 years ago
4 0

Answer:

16 times

Step-by-step explanation:

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Which number is in the solution set of the inequality 4x + 4 &gt; 36
nata0808 [166]

Step-by-step explanation:

4x > 36-4

4x > 32 (divide both sides of the inequality by 4 )

4x ÷ 4 > 32 ÷ 4

x > 8

5 0
3 years ago
Plz answer!!!!!!!!!!!!!!​
makkiz [27]

Answer:

7

Step-by-step explanation:

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7 0
2 years ago
What is 3/4 gallon in quarts?
Basile [38]

Answer:

3 quarts = 3/4 gallon

Step-by-step explanation:


5 0
3 years ago
susan is arranging coffee mugs on shelves in her shop. she wanta each shelf to have the same number of mugs.she only wants one c
yaroslaw [1]

The <em><u>correct answers</u></em> are:

7 mugs on each shelf; and 7 shelves for blue and 8 shelves for red.

Explanation:

To find the number of mugs that will fit on each shelf, we find the GCF (greatest common factor) of 49 and 56.  To do this, we find the prime factorization of each:

49 = 7(7)

56 = 7(8)

8 = 2(4)

4 = 2(2)

56 = 2(2)(2)(7)

The only common factor is 7, so this is the GCF.  This means that she needs to put 7 mugs on each shelf.

Since there are 49 blue mugs, she needs 49/7 = 7 shelves for them.

Since there are 56 red mugs, she needs 56/7 = 8 shelves for them.

8 0
3 years ago
-6n5x^3÷18nx^7<br>12m^8y^6÷-9my^4​
umka2103 [35]

Answer:

(-n^4 - 4 m^7 x^4 y^2)/(3 x^4)

Step-by-step explanation:

Simplify the following:

(-6 n^5 x^3)/(18 n x^7) + (12 m^8 y^6)/(-9 m y^4)

The gcd of -6 and 18 is 6, so (-6 n^5 x^3)/(18 n x^7) = ((6 (-1)) n^5 x^3)/((6×3) n x^7) = 6/6×(-n^5 x^3)/(3 n x^7) = (-n^5 x^3)/(3 n x^7):

(-1 n^5 x^3)/(3 n x^7) + (12 m^8 y^6)/(-9 m y^4)

Combine powers. (-n^5 x^3)/(3 n x^7) = (n^(5 - 1) x^(3 - 7) (-1))/3:

-(n^(5 - 1) x^(3 - 7))/3 + (12 m^8 y^6)/(-9 m y^4)

5 - 1 = 4:

-(n^4 x^(3 - 7))/3 + (12 m^8 y^6)/(-9 m y^4)

3 - 7 = -4:

-(n^4 x^(-4))/3 + (12 m^8 y^6)/(-9 m y^4)

The gcd of 12 and -9 is 3, so (12 m^8 y^6)/(-9 m y^4) = ((3×4) m^8 y^6)/((3 (-3)) m y^4) = 3/3×(4 m^8 y^6)/(-3 m y^4) = (4 m^8 y^6)/(-3 m y^4):

(4 m^8 y^6)/(-3 m y^4) - (n^4)/(3 x^4)

Combine powers. (4 m^8 y^6)/(-3 m y^4) = (4 m^(8 - 1) y^(6 - 4))/(3 (-1)):

-(n^4)/(3 x^4) + (4 m^(8 - 1) y^(6 - 4))/(-3)

8 - 1 = 7:

-(n^4)/(3 x^4) + (4 m^7 y^(6 - 4))/(-3)

6 - 4 = 2:

-(n^4)/(3 x^4) + (4 m^7 y^2)/(-3)

Multiply numerator and denominator of (4 m^7 y^2)/(-3) by -1:

-4/3 m^7 y^2 - (n^4)/(3 x^4)

Put each term in -(n^4)/(x^4×3) - (4 m^7 y^2)/3 over the common denominator 3 x^4: -(n^4)/(x^4×3) - (4 m^7 y^2)/3 = (-n^4)/(3 x^4) - (4 m^7 x^4 y^2)/(3 x^4):

-n^4/(3 x^4) - (4 m^7 x^4 y^2)/(3 x^4)

-n^4/(3 x^4) - (4 m^7 x^4 y^2)/(3 x^4) = (-n^4 - 4 m^7 x^4 y^2)/(3 x^4):

Answer: (-n^4 - 4 m^7 x^4 y^2)/(3 x^4)

5 0
3 years ago
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