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True [87]
2 years ago
8

Ms. Lapido bought a car and pay for it $20.000.At the end of 10 years the car has no value whatsoever. Assuming that the car is

losing the same amount of value per year : a)What will be the value of the car after 3 years? b)What is going to be the depreciation of the car per year? c)How can you represent the situation in a coordinate plane? Remember to label the axis and use the appropriate scale​
Mathematics
1 answer:
Leviafan [203]2 years ago
4 0

Answer:

A) the value of the car will be 13,333.34 after 3 years ( not sure )

B) the depreciation of the car will be 2222.22 per year ( not sure)

C)  i do not know

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20PTS Question On Pic Thx
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Answer:

  (a)  $3800

  (b)  (a) -- April to May

Step-by-step explanation:

<h3>(a)</h3>

The least amount is found at the lowest point on the graph. That point is in May. It is on the line between 3700 and 3900, so the amount is $3800.

The least donation amount is a month is $3800.

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<h3>(b)</h3>

The greatest month-to-month decrease is found where the line on the graph has the steepest negative slope. There are two segments with negative slope:

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The greatest decrease occurred April to May.

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2 years ago
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A dog chases a squirrel. The dog is originally 200 feet away from the squirrel. The dog's speed is 150 feet per minute. The squi
Dafna11 [192]

Answer:

15 seconds

Step-by-step explanation:

If you make a table of values for the dog and the squirrel using d = rt, then the rates are easy:  the dog's rate is 150 and the squirrel's is 100.  The t is what we are looking for, so that's our unknown, and the distance is a bit tricky, but let's look at what we know:  the dog is 200 feet behind the squirrel, so when the dog catches up to the squirrel, he has run some distance d plus the 200 feet to catch up.  Since we don't know what d is, we will just call it d!  Now it seems as though we have 2 unknowns which is a problem.  However, if we solve both equations (the one for the dog and the one for the squirrel) for t, we can set them equal to each other.  Here's the dog's equation:

d = rt

d+200 = 150t

And the squirrel's:

d = 100t

If we solve both for t and set them equal to each other we have:

\frac{150}{d+200} =\frac{100}{d}

Now we can cross multiply to solve for d:

150d = 100d + 20,000 and

50d = 20,000

d = 400

But we're not looking for the distance the squirrel traveled before the dog caught it, we are looking for how long it took.  So sub that d value back into one of the equations we have solved for t and do the math:

t=\frac{100}{d}=\frac{100}{400} =\frac{1}{4}

That's 1/4 of a minute which is 15 seconds.

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3 years ago
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It’s Edgar or 40 miles
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3 years ago
What is the sale of the original price?
Lady bird [3.3K]

Answer:

50 dollars

Step-by-step explanation:

40*25%=10

40+10= 50 dollars

Add it to find the original sales price which would end up being 50 dollars! Hope this helps, have a good day. c;

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