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3 years ago

I need help please with this answer

Mathematics

2 answers:

Firlakuza [10]3 years ago

8 0

320 cm! Hope I help!!!!!!!

babymother [125]3 years ago

3 0

First, find the area of the big rectangle:

A=lw

A= 17*20

A=340 cm^2

Next, find the area of the trapezoid.

A=base1+base2. *H
———————-
2

A=6+12
———- * 6
2

A= 54 cm^2

Now, subtract the area of the trapezoid from the bigger rectangle.

340-54=286

So, the shaded area is 286 cm^2. That’s ur answer!

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Can you please help me

Ket [755]

Answer:

The scale factor for the dilation of rectangle ABCD to rectangle MNOP is $\frac{3}{4}$ ⇒ B

Step-by-step explanation:

In similar rectangles, their corresponding dimensions are proportional, which means $\frac{L_{1} }{L_{2}}$ = $\frac{W_{1} }{W_{2}}$ , where L is the length and W is the width

∵ Rectangle ABCD is similar to rectangle MNOP

∴ Their dimensions are proportional

∵ The dimensions of rectangle ABCD are 6 m, 14 m

∴ L $_{1}$ = 14 and W $_{1}$ = 6

∵ The dimensions of rectangle MNOP are 4.5 m, 10.5 m

∴ L $_{2}$ = 10.5 and W $_{2}$ = 4.5

∵ The rectangle MNOP is the image of rectangle ABCD after dilation

→ To find the scale factor of dilation find the ratio between the

corresponding dimensions in the two rectangles (image/pre-image)

∵ $\frac{L_{2} }{L_{1}}$ = $\frac{10.5}{14}$ = $\frac{3}{4}$

∵ $\frac{W_{2} }{W_{1}}$ = $\frac{4.5}{6}$ = $\frac{3}{4}$

∴ The scale factor for the dilation is $\frac{3}{4}$

The scale factor for the dilation of rectangle ABCD to rectangle MNOP is $\frac{3}{4}$

6 0

2 years ago

Please help<br><br> I need help creating a table of value for this equation

Fed [463]

Answer:

Create the table and choose a set of x values. Substitute each x value (left side column) into the equation. Evaluate the equation (middle column) to arrive at the y value. An Optional step, if you want, you can omit the middle column from your table, since the table of values is really just the x and y pairs.

Step-by-step explanation:

Specify a name for the function.

Specify a name and data type for each input parameter.

Specify the routine attributes.

Specify the RETURNS TABLE keyword.

Specify the BEGIN ATOMIC keyword to introduce the function-body.

Specify the function body.

7 0

2 years ago

Which expressions have a value of 16/81? Check all that apply.

lana [24]

Which expression have a value of 16/81? check all that apply. (2/3)^4, (16/3)^4, (4/81)^2, and (4/9)^2

Answer:

First and last option is correct.

$(\frac{2}{3})^{4}=\frac{16}{81}$

$(\frac{4}{9})^{2}=\frac{16}{81}$

Step-by-step explanation:

Given:

There are four options.

(2/3)^4, (16/3)^4, (4/81)^2, and (4/9)^2

We need to check all given options for value of 16/81.

Solution:

Using rule.

$(\frac{a}{b})^{n}=\frac{a^{n}}{b^{n}}$

Solve for option $(\frac{2}{3})^4$ .

$(\frac{2}{3})^{4}=\frac{2^4}{3^4}=\frac{2\times 2\times 2\times 2}{3\times 3\times 3\times 3}=\frac{16}{81}$

Solve for option $(\frac{16}{3})^4$ .

$(\frac{16}{3})^{4}=\frac{16^4}{3^4}=\frac{16\times 16\times 16\times 16}{3\times 3\times 3\times 3}=\frac{65536}{81}$

Solve for option $(\frac{4}{81})^2$ .

$(\frac{4}{81})^{2}=\frac{4^2}{81^2}=\frac{4\times 4}{81\times 81}=\frac{16}{6561}$

Solve for option $(\frac{4}{9})^2$ .

$(\frac{4}{9})^{2}=\frac{4^2}{9^2}=\frac{4\times 4}{9\times 9}=\frac{16}{81}$

Therefore, expression $(\frac{2}{3})^4$ and $(\frac{4}{9})^2$ have a value of $\frac{16}{81}$ .

6 0

3 years ago

Which expressions are differences of squares?

Lina20 [59]

Difference of 2 perfec squares is
(a^2)-(b^2)

if the exponents are both even and the coeficient (the number in front) are perfect squares, then it is difference t 2 perfect squares

first one
8 is not perfect square

2nd one
(4e^4)^2-(9g^2)^2

third
25 is odd, so it cannot be split up into 2 nice numbers

4th
(11m^9)^2-(3n^5)^2

8 0

2 years ago

Thirteen less than six times a number is equal to 11 more than four times the number

solong [7]

Let us pretend x is the number.

The equation will be 13-6x=11+4x.

Solve.......

X=2/10

6 0

2 years ago