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jonny [76]
3 years ago
7

I need help please with this answer

Mathematics
2 answers:
Firlakuza [10]3 years ago
8 0

320 cm! Hope I help!!!!!!!

babymother [125]3 years ago
3 0
First, find the area of the big rectangle:

A=lw

A= 17*20

A=340 cm^2


Next, find the area of the trapezoid.

A=base1+base2. *H
———————-
2

A=6+12
———- * 6
2

A= 54 cm^2


Now, subtract the area of the trapezoid from the bigger rectangle.

340-54=286

So, the shaded area is 286 cm^2. That’s ur answer!
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I need help with this. I'm stuck. PLEASE SAVE ME
vagabundo [1.1K]

Answer: Its the one.

Step-by-step explanation:

Your going to subtract 2 from each sides making the equation, -5 is less than or equal to 25, then your gonna divide -5 by 25, which will give you -5, and then the sign will switch to greater than or equal to because you divided by a negative number. The dot on the number line will be solid because the sign is greater than or equal to. You're welcome :)

7 0
3 years ago
KL = 4x +3.<br> JK = 4x + 2, and<br> JL = 45<br> Find KL.
lbvjy [14]

Answer:

KL=23

Step-by-step explanation:

We are given the length of the whole line and its two halves. Since JK and KL make up the line JL, adding them together would make the line JL.

(4x+3)+(4x+2) = 45

8x+5=45

8x=40

x=5

Now we can plug the value of x back into the expression we were given for the line KL.

4(5)+3

23

7 0
3 years ago
David bought a poster for an art project. The poster is 2.7 ft wide and 3.9 ft tall. What is the area of the poster? Enter your
algol13
10.53 ft is the Area. :D:D
7 0
3 years ago
The area of a square is 121 square feet. What is the perimeter of the square
Ugo [173]

Answer:

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Step-by-step explanation:

square root of 121 is 11

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6 0
3 years ago
(b-c)3 +(c-d) raise to3 3+(d-b)3
Juliette [100K]

Answer:3 b − 2 c− d , t o 3 , 3 + 3d − 3 b

Step-by-step explanation:

( b − c ) ⋅ 3 + ( c -d )  raise  t o  3   3 + ( d − b ) ⋅ 3

Write the problem as a mathematical expression.

( b − c ) ⋅ 3 +( c − d )  raise  t o3   3+ ( d − b) ⋅ 3

Remove parentheses.

( b − c) ⋅ 3 + c − d , t o 3 , 3 + ( d − b ) ⋅ 3

Simplify each term.

Apply the distributive property.

b ⋅ 3 − c ⋅ 3 + c− d

Move  3  to the left of  b . 3 ⋅ b − c ⋅ 3 + c − d

Multiply  3  by  − 1  ⋅ 3 b − 3 c + c − d

Add  − 3 c  and  c. 3 b − 2 c − d , t o 3 , 3 + ( d − b ) ⋅ 3

Simplify each term.

Apply the distributive property.

3 + d  ⋅ 3 − b  ⋅ 3

Move  3  to the left of  d . 3 + 3 ⋅ d − b ⋅ 3

Multiply  3  by  − 1 . 3 + 3 d − 3 b

4 0
3 years ago
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