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3 years ago

Rush! please please help

Mathematics

1 answer:

kodGreya [7K]3 years ago

5 0

Answer:

it's the one on the bottom right of the screen

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Mrs. taylor bought a water tube to pull behind her boat. The tube cost $87.00 and 9% sales tax was added at the register. Ms. ta

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She should get $12.91 back

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3 years ago

A ball is dropped from a height of 30 feet and each time it hits the ground it bounces 0.75 of the previous height. What is the

dimulka [17.4K]

30 x 0.75 = 22.5 .............(1st)

22.5 x 0.75 = 16.875 ......(2nd)

16.875 x 0.75 = 12.66 ....(3rd)

ANSWER: C) 12.66

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3 years ago

Which sequence of transformations could be used to map triangle MNO onto M”N”O”?

Bumek [7]

Answer:

Option D

Step-by-step explanation:

I dont really know but i think its D

3 0

3 years ago

Read 2 more answers

HELP ASAP! WILL MARK BRAINLIEST!!

malfutka [58]

Answer:

r = 6

Step-by-step explanation:

V(cyl) = π · r² · h

144π = π · r² · 4

144 = r² · 4

<u>144</u> = r²

r = $\sqrt{144}$ ÷ $\sqrt{4}$

r = 12/2

r = 6

5 0

3 years ago

For every integer k from 1 to 10, inclusive the "k"th term of a certain sequence is given by (−1)(k+1)∗(12k). If T is the sum of

Katena32 [7]

Answer:

Option D. is the correct option.

Step-by-step explanation:

In this question expression that represents the kth term of a certain sequence is not written properly.

The expression is $(-1)^{k+1}(\frac{1}{2^{k}})$ .

We have to find the sum of first 10 terms of the infinite sequence represented by the expression given as $(-1)^{k+1}(\frac{1}{2^{k}})$ .

where k is from 1 to 10.

By the given expression sequence will be $\frac{1}{2},\frac{(-1)}{4},\frac{1}{8}.......$

In this sequence first term "a" = $\frac{1}{2}$

and common ratio in each successive term to the previous term is 'r' = $\frac{\frac{(-1)}{4}}{\frac{1}{2} }$

r = $-\frac{1}{2}$

Since the sequence is infinite and the formula to calculate the sum is represented by

$S=\frac{a}{1-r}$ [Here r is less than 1]

$S=\frac{\frac{1}{2} }{1+\frac{1}{2}}$

$S=\frac{\frac{1}{2}}{\frac{3}{2} }$

S = $\frac{1}{3}$

Now we are sure that the sum of infinite terms is $\frac{1}{3}$ .

Therefore, sum of 10 terms will not exceed $\frac{1}{3}$

Now sum of first two terms = $\frac{1}{2}-\frac{1}{4}=\frac{1}{4}$

Now we are sure that sum of first 10 terms lie between $\frac{1}{4}$ and $\frac{1}{3}$

Since $\frac{1}{2}>\frac{1}{3}$

Therefore, Sum of first 10 terms will lie between $\frac{1}{4}$ and $\frac{1}{2}$ .

Option D will be the answer.

3 0

3 years ago