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fgiga [73]
2 years ago
10

PLEASE HELP ME THIS IS URGENT

Mathematics
1 answer:
igomit [66]2 years ago
4 0

Split this figure out. Find the area of the square, as well as the rectangle.

First, the square

A= 4 x 3

A= 12 ft^2

Therefore, the square has an area of 12ft^2.

Then, the rectangle.

We must first find the length of the unknown side.

We have two measurements of 3ft on each side, as well as the middle measurement of 4ft.

So,

3+3+4=10

Now, find the area.

A= 2 x 10

A=20ft^2

Add the areas.

20+12=32ft^2

Therefore, the area of the figure is 32ft^2.

I hope this is correct. Best of luck.

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Please show your work and explain it.
Maru [420]

Answer:

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Step-by-step explanation:

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Next we factor what we can so we can further simplify the rest of the equation:

=\dfrac{(x^2+4x+4)(3x-12)}{(x^2-6x+8)(6x+12)}\\\\=\dfrac{(x+2)(x+2)(3x-12)}{(x^2-6x+8)(6(x+2))}\\\\

We can now cancel out (x+2)

=\dfrac{(x+2)(3x-12)}{(x^2-6x+8)(6)}

Next we factor out even more:

=\dfrac{(x+2)(3)(x-4)}{(x-2)(x-4)(6)}

We cancel out x-4 and reduce the 3 and 6 into simpler terms:

=\dfrac{(x+2)(1)}{(x-2)(2)}

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Answer:

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5 x 8 = 40

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