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Answer:
The average speed over the time interval from 9 A.M. to noon was of 33.33 mph.
Step-by-step explanation:
The average speed is given by the following equation:
![v = \frac{d}{t}](https://tex.z-dn.net/?f=v%20%3D%20%5Cfrac%7Bd%7D%7Bt%7D)
From 10A.M. to noon.
You traveled at 50mph during 2 hours. So how long you traveled?
![50 = \frac{d}{2}](https://tex.z-dn.net/?f=50%20%3D%20%5Cfrac%7Bd%7D%7B2%7D)
![d = 50*2](https://tex.z-dn.net/?f=d%20%3D%2050%2A2)
![d = 100](https://tex.z-dn.net/?f=d%20%3D%20100)
You traveled 100 miles.
What was your average speed over the time interval from 9 A.M. to noon
From 9 A.M. to 10 A.M, you did not travel.
From 10 P.M. to noon, 100 miles.
So 100 miles during 3 hours.
![v = \frac{d}{t} = \frac{100}{3} = 33.33](https://tex.z-dn.net/?f=v%20%3D%20%5Cfrac%7Bd%7D%7Bt%7D%20%3D%20%5Cfrac%7B100%7D%7B3%7D%20%3D%2033.33)
The average speed over the time interval from 9 A.M. to noon was of 33.33 mph.
Answer:
324
Step-by-step explanation:
given that in a poll, 74% of the people polled answered yes to the question "Are you in favor of the death penalty for a person convicted of murder?"
i.e. Sample proportion ![p=0.74\\q =1-p =0.26\\](https://tex.z-dn.net/?f=p%3D0.74%5C%5Cq%20%3D1-p%20%3D0.26%5C%5C)
Margin of error = 4% = 0.04
Confidence level =90%
Z critical value for 90% = 1.645
Margin of error = 1.645 * std error
Hence std error = ![\frac{0.04}{1.645} \\=0.0243](https://tex.z-dn.net/?f=%5Cfrac%7B0.04%7D%7B1.645%7D%20%5C%5C%3D0.0243)
Std error is also equal to
![\sqrt{\frac{pq}{n} } =\sqrt{\frac{0.74(0.26)}{n} } =0.0243\\\sqrt{n} =18..05\\n = 325.83~324](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7Bpq%7D%7Bn%7D%20%7D%20%3D%5Csqrt%7B%5Cfrac%7B0.74%280.26%29%7D%7Bn%7D%20%7D%20%3D0.0243%5C%5C%5Csqrt%7Bn%7D%20%3D18..05%5C%5Cn%20%3D%20325.83~324)
Sample size should be 324.
The formula is sample size = (Z critical value)^2 (pq)/(Margin of error )^2
The answer would be, 0.55555555556
hope this helps :-)