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3 years ago

Find the area of this dog crate

Mathematics

1 answer:

patriot [66]3 years ago

3 0

Where’s the dog crate?

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A shirt that normally sells for $28 is on sale at a 10% discount. What is the sale price of the shirt?

sdas [7]

The shirt would then be $25.20

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4 years ago

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sweet [91]

Answer:

Step-by-step explanation:

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3 years ago

The electric cooperative needs to know the mean household usage of electricity by its non-commercial customers in kWh per day. A

vekshin1

Answer:

$15.7-2.58\frac{2.3}{\sqrt{1731}}=15.6$

$15.7+2.58\frac{2.3}{\sqrt{1731}}=15.8$

We are 99% confident that the true mean of electricity comsumption is between (15.6 and 15.8) kWh

Step-by-step explanation:

Information provided

$\bar X= 15.7$ represent the sample mean for the usage of electricity

$\mu$ population mean (variable of interest)

$\sigma= 2.3$ represent the population standard deviation

n=1731 represent the sample size

Confidence interval

The confidence interval for the mean is given by the following formula if we know the population deviation:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

The Confidence level provided is 0.99 or 95%, the value of significance is $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that $z_{\alpha/2}=2.58$

And replacing we got:

$15.7-2.58\frac{2.3}{\sqrt{1731}}=15.6$

$15.7+2.58\frac{2.3}{\sqrt{1731}}=15.8$

We are 99% confident that the true mean of electricity comsumption is between (15.6 and 15.8) kWh

7 0

4 years ago

Evaluate: 3-3 =<br> A. 1/9 B. -27 C. 1/27 D. -9

ziro4ka [17]

The answer for this question is C

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3 years ago

Greg is the lead scorer on his school’s hockey team. He scores a goal 3 out of every 4 attempts. Design a simulation to determin

Karolina [17]

The way i solved the probability percentage was 3/4 = x/100, which means his probability of making it in the goal was 75%. if it was out of five, he’d make 3.75 goals, going by the percentage. hope this helps you in some way

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3 years ago