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#1
a + b • 3 = 3a + 3b
No
Actual equation formed:-
a + 3b = 3a + 3b
#2
Yes
#3
a + b • 3 = a + 3b
Yes
#4
a + 3b • 3= 3a + 6b
No
Actual equation formed:-
a + 9b
#5
a + 3b • 3 = a + 9b
Yes
Rule applies:-
BODMAS
B - brakets
O - on/off
D- divide
M - multiply
A - add
S - subtract
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Answer:
The probability that more than 6 samples are needed to have 2 mutations is P=0.866.
Step-by-step explanation:
This question can be analized with the binomial distribution.
We need to calculate the probability that more of 6 samples are needed to have 2 samples with mutations.
This is equal to the proability of taking 2 samples and getting one mutation or less.
Then we have a binomial distribution with n=6 and p=0.11:

A²+b²=c²
39²+b²=89²
1521+b²=7921
subtract 1521 from both sides
b²=6400
so then you square both sides
√6400
80
Answer:
2.970600004839 × 10^5
Step-by-step explanation:
First, we add up these 2 numbers.
297,060 + 0.0004839 = 297060.0004839
Then, we convert that into scientific notation.
297060.0004839 = 2.970600004839 × 10^5
Finally, we check if it's right.
10^5 = 100000
2.970600004839 * 100000 = 297060.0004839
Hope this helps.