Answer:
Step-by-step explanation:
You are being asked to compare the value of a growing infinite geometric series to a fixed constant. Such a series will always eventually have a sum that exceeds any given fixed constant.
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<h3>a)</h3>
Angelina will get more money from the Choice 1 method of payment. The sequence of payments is a (growing) geometric sequence, so the payments and their sum will eventually exceed the alternative.
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<h3>c)</h3>
For a first term of 1 and a common ratio of 2, the sum of n terms of the geometric series is given by ...
Sn = a1×(r^n -1)/(r -1) . . . . . . . . . . series with first term a1, common ratio r
We want to find n such that ...
Sn ≥ 1,000,000
1 × (2^n -1)/(2 -1) ≥ 1,000,000
2^n ≥ 1,000,001 . . . . add 1
n ≥ log(1,000,001)/log(2) . . . . . take the base-2 logarithm
n ≥ 19.93
The total Angelina receives from Choice 1 will exceed $1,000,000 after 20 days.
A would be the answer to this question
Answer:
Step-by-step explanation:
<u>Carlos made:</u>
<u>Lily made:</u>
<u>Together they made:</u>
- 12C + 35 + 12L = 12(C + L) + 35
Lily is right. We don't know what 120 means in Carlos's equation, he should put 12L for Lily.
-4/8 i think that is right not sure tho so you might wanna wait for ohter answer
Answer:
triangle JKL
Step-by-step explanation:
This is because the lengths of each side JKL is a factor to ABC
respectively .
AB=12,JK=36
AC=13,JL=39
BC=5,KL=25
I hope you understand
