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Amanda [17]
3 years ago
10

A landscaping company charges customers for lawn care based on the area of their yards. Mr. Jones was charged $52 for his yard,

which is 40 feet by 65 feet. If a neighbor's yard is 50 feet by 80 feet, what would the neighbor be charged based on how much Mr. Jones was charged?
Mathematics
2 answers:
svp [43]3 years ago
7 0

Answer: The neighbor would be charged $80

Step-by-step explanation:

The dimensions of Mr Jones's yard are 40 feet by 65 feet. This means that the shape of Mr Jones's yard is rectangular. The formula for determining the area of a rectangle is length × width. The area of the yard would be

40 × 65 = 2600 square feet

Mr. Jones was charged $52 for his yard. This means that the amount that he was charged per square foot would be 52/2600 = $0.02

If a neighbor's yard is 50 feet by 80 feet, it means that the area of his yard would be 50 × 80 = 4000 square feet. The amount that the neighbor would be charged is

4000 × 0.02 = $80

Zanzabum3 years ago
6 0

Answer:

$80

Step-by-step explanation:

Area of Mr Jones's yard = 40 * 65 square feet

= 2600 square feet

Mr. Jones was charged $52 for the yard.

Therefore cost per square feet = 52/2600 = $0.02 per square feet

Area of neighbor's yard = 50 * 80 = 4000 square feet

Hence the neighbor will be charged 0.02 * 4000 = $80

For the area corresponding to the yard of size 4000 square feet, he will have to pay $80 to the landscaping company.

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