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3 years ago

Solve the equation - 2(m -30) = -6m A-15 B-13 C-8 D8

Mathematics

1 answer:

hram777 [196]3 years ago

3 0

Answer:

D is your answer

Step-by-step explanation:

-2(m-30)=-6m

-2m+60=-6m

-8m+60=0

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What is g(x) I need your help

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Answer:

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Step-by-step explanation:

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3 years ago

A 90% confidence interval for the average salary of all CEOs in the electronics industry was constructed using the results of a

Stella [2.4K]

Answer:

b) We are 90% confident that the mean salary of all CEOs in the electronics industry falls in the interval $139,048 to $154,144.

Step-by-step explanation:

Confidence interval:

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We build from a sample.

Between a and b.

Intepretation: We are x% sure that the population mean is between a and b.

In this question:

90%

45 CEO's

Between ($139,048, $154,144).

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The correct answer is:

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3 years ago

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vekshin1

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3 years ago

What is the explicit formula for the sequence below?<br><br> 4, -12, 36, -108 ...

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3 years ago

Read 2 more answers

A jar contains 8 red marbles numbered 1 to 8 and 7 blue marbles numbered 1 to 7. A marble is drawn at random from the jar. Find

Shkiper50 [21]

Answer:

Therefore the probability that the marble is blue or even numbered is $\frac{11}{15}$

Step-by-step explanation:

Probability: The ratio of favorable outcomes to the total outcomes.

It is denoted by P.

$Probability= \frac{\textrm{favorable outcomes}}{\textrm{Total outcomes}}$

Given that a jar contains 8 red marbles and 7 blue marbles.

Total number of marbles = (8+7) = 15

Let A = Event of getting a blue marble

B= Event of getting of even marble.

Even number blue marbles are 2, 4,6

Even number red marbles are 2, 4,6,8

The number of even marbles are =(3+4)=7

The probability of getting a blue marble is P(A)

$=\frac{\textrm{Total number of blue marbles}}{\textrm{Total number of blue marbles}}$

$=\frac{7}{15}$

The probability of getting a even marble is P(B)

$=\frac{\textrm{The number of even number marbles}}{\textrm{Total number of marbles}}$

$=\frac{7}{15}$

The probability of getting a even numbered blue marble P(A∩B)

$=\frac{3}{16}$

P(blue marble or even- numbered)

=P(A∪B)

=P(A)+P(B)-P(A∩B)

$=\frac{7}{15} +\frac{7}{15}-\frac{3}{15}$

$=\frac{11}{15}$

Therefore the probability that the marble is blue or even numbered is $\frac{11}{15}$

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4 years ago