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1 answer:
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Answer:
Length of the shorter diagonal is 8.68 cm.
Step-by-step explanation:
Length of the side AB = 11 cm
Length of side BC = 5 cm
Angle between these sides, m∠ABC = 50°
By cosine rule in ΔABC,
AC² = AB² + BC² - 2AB.BC.cos B
AC² = (11)² + 5² - 2(11)(5)cos50°
AC² = 121 + 25 - 70.71
AC = √(75.29)
AC = 8.68 cm
By the property of parallelogram,
m∠B + m∠C = 180° [Interior consecutive angles]
50° + m∠C = 180°
m∠C = 130°
Similarly, In ΔBCD,
BD² = BC² + CD² - 2BC.CD.cos130°
BD² = (5)² + (11)² - 2(5)(11)cos130°
BD² = 25 + 121 + 70.71
BD² = 216.71
BD = 14.72 cm
Therefore, length of the shorter diagonal will be 14.72 cm.
Answer:
Option D is correct.
VS = 20 units.
Step-by-step explanation:
The complete question is contained in the attached image to this answer.
From the image attached and the additional information about the triangles, it is evident that that triangle VSW is similar to triangle QSR.
Hence, we can write the ratio as
(VS/QS) = (VW/QR)
VS = 2a
QS = 2 × VS = 2 × 2a = 4a
VW = 2a - 2
QR = 3a + 6
(2a)/(4a) = (2a - 2)/(3a + 6)
Cross multiplying,
2a (3a + 6) = 4a (2a - 2)
3a + 6 = 2 (2a - 2)
3a + 6 = 4a - 4
4a - 3a = 6 + 4
a = 10
VS = 2a = 20 units.
Hope this Helps!!!
