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Juliette [100K]
3 years ago
14

Kieth ran a marathon. It took 3 hours and 2 mins to run 26 miles. If he ran at the same rate for the whole race, how many minute

s did it take him to run each mile?
Mathematics
1 answer:
baherus [9]3 years ago
7 0
It took him 7 minutes to run each mile.

Firstly, covert the time into minutes.
3 * 60 = 180 minutes 
180 + 2 = 182 minutes

Now in order to find how long he ran each mile,
divide 182 by 26
182/26 = 7 minutes
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Kiara desea contratar el servicio de una línea telefónica con internet para realizar sus clases virtuales. Si el costo de una lí
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a) Kiara ha adquirido una línea de telefonía móvil con internet a un Coste Fijo de 10 soles y un Tasa de Consumo de 1,5 soles por hora consumida.

b) El Coste total por 48 horas de consumo de la línea telefónica con internet es 82 soles.

a) Nota - Puesto que la ecuación que describe el Coste ya existe en el enunciado, entonces se entiende el verbo <em>"Expresa"</em> como <em>"Describa en sus propias palabras"</em>.

Como puede apreciarse el Coste de la línea telefónica móvil aumenta linealmente con el Tiempo de consumo por parte del usuario. En consecuencia, la función de Coste queda definida como sigue:

C(t) = C_{o} + r\cdot t (1)

Donde:

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Entonces, tenemos que Kiara ha adquirido una línea de telefonía móvil con internet a un Coste Fijo de 10 soles y un Tasa de Consumo de 1,5 soles por hora consumida.

b) Una característica de las Funciones Lineales es que tanto su Dominio como Rango comprenden al Conjunto de todos los Números Reales, al ser de Pendiente constante esta Función.

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C(48) = 10 + 1,5\cdot (48)

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Invitamos a ver este problema sobre Costes: brainly.com/question/15723794

7 0
3 years ago
Each person in a group of college students was identified by graduating year and asked when he or she preferred taking classes:
swat32

Answer:

<em>0.615</em>

Step-by-step explanation:

The frequency table is attached below.

We have to calculate, the probability that the student preferred morning classes given he or she is a junior.

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We know that,

P(A\ |\ B)=\dfrac{P(A\ \cap\ B)}{P(B)}

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P(\text{Morning }|\text{ Junior})=\dfrac{P(\text{Morning }\cap \text{ Junior})}{P(\text{Junior})}

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