I need help with problem 27
1 answer:
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Answer:
The ratio of the area of the school banner to the area of the sign is <u>1944 cubic inches : 192.61 cubic inches.</u>
Step-by-step explanation:
Given:
A rectangular school banner has a length of 54 inches and a width of 36 inches. A sign is made that is similar to the school banner and has a length of 17 inches.
Now, to find the ratio of the area of the school banner to the area of the sign.
Dimensions of school banner :
Length = 54 inches.
Width = 36 inches.
Dimension of school sign:
Length = 17 inches.
So, to we find the width of sign by using cross multiplication method:
Let the width be
So, 54 is equivalent to 36.
Thus, 17 is equivalent to
By cross multiplying we get:
Dividing both sides by 54 we get:
Thus, the width of sign = 11.33 inches.
Now, to get the ratio of the area of the school banner to the area of the sign:
Area of the school banner : Area of the school sign.
=
=
Therefore, the ratio of the area of the school banner to the area of the sign is 1944 cubic inches : 192.61 cubic inches.
Answer:
Tan B = 12/5
Sin B = 12/13
Cos B = 5/13
Step-by-step explanation:
sine B = opposite (12)/hypotenuse (13)
= 12/13
Cosine B = adjacent/hypotenuse
= 5/13
Tangent B = opposite/adjacent
= 12/5
Here is a picture that can always help you with the three trig ratios.
