Answer:
Domain and range » Tips for entering queries. Enter your queries using plain English. To avoid ambiguous queries, make sure to use parentheses where necessary. Here are some examples illustrating how to ask for the domain and range. domain of log(x) (x^2+1)/(x^2-1) domain; find the domain of 1/(e^(1/x)-1) function domain: square root of cos(x)
Step-by-step explanation:
Answer:
A≈28.26 in^2
Step-by-step explanation:
We know the diameter is 6
We can find the radius
r = d/2
r =6/2 =3 inches
The area of a circle is given by
A = pi *r^2
A = pi*3^2
A = pi*9
We will use 3.14 to approximate pi
A ≅(3.14) *9
A≈28.26 in^2
In degrees,
arccos(0.36) = 68.89980398 ≈ 68.9°
In radians,
arccos(0.36) = 1.202528433 ≈ 1.20
Answer:
Step-by-step explanation:
To properly apply the substitution method, it will be better for us to rearrange the system of equations to have similar variables on the same side
We can simply evaluate equation 1 to have
y = -20
From the first equation alone, we can evaluate the value of y as -20. This is because only one unknown is present in equation one, hence a single equation is sufficient enough to evaluate it. If to unknowns were present, the two equations would have been utilized to evaluate the solution.
Ahh thank you so much !! <3
