Answer:
b.(4,6/7)
Step-by-step explanation:
i hope i was able to help with the question
Answer:
Step-by-step explanation:
We can use the decay equation:

- M(0) is the initial mass
- M is the mass after t (1000 days) time
- λ is the decay constant
But:

So, we can rewrite the initial equation:

Now, we just need to solve it for t(1/2):


I hope it helps you!
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Hope this helps you
Answer:
5^27 is the simplified version
Step-by-step explanation:
5
Answer:
-45
Step-by-step explanation:
(15+6-2)+(-52-18+6)
(21-2)+(-70+6)
(19)+-(-64)
19-64
-45