20 POINTS

Mathematics

1 answer:

denis-greek [22]2 years ago

8 0

Answer:

c. 441ft^2

Step-by-step explanation:

Area is height times length and since it's a square, safe to say that the sides are equal in length. So square root both of the given areas of the 2 square:

$\sqrt{841}$ = 29

$\sqrt{400}$ = 20

Now u have side b and c of the triangle, it's a right triangle so use the Pythagorean theorem a^2 + b^2 = c^2

a^2 + b^2 = c^2

a^2 + 20^2 = 29^2

a^2 + 400 = 841

subtract 4 from both sides

a^2 = 441

square root both sides

$\sqrt{a^2} = \sqrt{441}$

a = 21

Now the side a of the triangle is also a side of the small square therefore

21^2 = 441

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Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}}$