Answer:
9 and 12
Step-by-step explanation:
The ordered pairs that are located 8 units away from the point (2, 1) are; (-6,1), (10,1), (2,-7) and (2,9)
<h3>Ordered pairs and Distance.</h3>
The ordered pairs which can be 8 units away from the point, (2, 1) are pairs in which case, either x or y coordinates or both are 8 units from the given pair of coordinates (2,1).
Hence, the following pair of coordinates have x or y coordinates which are 8 units away from the x or y coordinates of the given pair of coordinates.
Read more on coordinates;
brainly.com/question/3447129
No, for example, if you had the prime number 23, and you switched the numbers around, it is 32. 32 is not a prime number.
Given:
Endpoints of segment AB are A(- 18, 5) and B(- 4, 5).
Point Z is located exactly 1/8 of the distance from A to B.
To find:
The value of the x-coordinate of point Z.
Solution:
Point Z is located exactly 1/8 of the distance from A to B.
AZ:AB=1:8
AZ:ZB = AZ:(AB-AZ)= 1:(8-1) = 1:7
It means point Z divided segment AB in 1:7.
Using section formula, the x coordinate of point Z is
Therefore, the required x-coordinate of point Z is -16.25.
Answer:
its alot to explain but i will try to make it as simple as possible
Step-by-step explanation:
your first goal is to make each problem into the form ax^2+bx+c=0
number 1, 2, 7 and 8 is already done for you
now all you have to do is plug in each number in the standard form into the quadtratic formula.
basically at this point you can just use your calculator to do the rest of the work. dont forget parentheses so it doesnt get confused...
or you can perform the algebraic work.. its all just a matter of plugging in the right numbers into the quadratic formula...
cant really do the work for you since im on my phone. but yeah all you need to do step one is transform each problem into ax^2+bx+c=0 form
then step 2, plug in each number in to the quadtratic formula. from there calculate using basic algebraic rules
