<span>"In order to get the Least Common Multiple of 50 and 20 we need to factor each value and then we need to choose all of the factors which appear in any column and then multiply them."
50: 2 55
20: 225
LCM: 2255
</span><span>The (LCM) is: 2 x 2 x 5 x 5 = 100
</span>
<span>"To find the Greates Common Factor (GCF) of 20 and 50 we need to factor each value first and then choose all the copies of factors and then multiply them."
</span>
<span>20: 255
</span>
50: 55
The GCF is: 2 and 5 so you need to multiply and then you will get The Greates Common Factor. The greates common factor is: 2 x 5 = 10
Answer:
(a) I attached a photo with the diagram.
(b) 
(c) 1/4
(d) 4
(e) 
Step-by-step explanation:
(a) I attached a photo with the diagram.
(b) The easiest way to think about this part is in terms of combinatorics. Think about it like this.
To begin with, look at the three each level of the three represents a possible outcome of throwing the coin n-times. If you throw the coin 3 times at the end in total there are 8 possible outcomes. But The favorable outcomes are just 2.
1 - Your first outcome is HEADS and all the others are different except the last one.
2 - Your first outcome is TAILS and all the others are different except the last one.
Therefore the probability of the event is

(c)
P(X = 0) = 0 because it is not possible to have two consecutive tails or heads.

(d)
Remember that this is a geometric distribution therefore
, in this case
so
and
![E[X+1]^2 = ( E[X] +1 )^2 = (1+1)^2 = 2^2 = 4](https://tex.z-dn.net/?f=E%5BX%2B1%5D%5E2%20%3D%20%28%20E%5BX%5D%20%2B1%20%29%5E2%20%20%3D%20%281%2B1%29%5E2%20%3D%202%5E2%20%3D%204)
Also
(e)
This is a geometric distribution so its variance is

And using properties of variance

Let the bushels of wheat is b and weight of the wheat is w.
We can say that more the bushels of wheat more will be the weight of the wheat.
Hence, the quantities vary directly.
Therefore, we have
, where k is the constant of variation.
Now, we have been given that 5 bushels of wheat weigh 136 kg. Thus, we have

Thus, the constant of variation is 
Now, we have been given 3.5 bushels of wheat. Hence, we have

Therefore, 3.5 bushels of wheat weigh 95.2 kg