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mylen [45]
3 years ago
7

a hockey season ticket holder pays $99.26 for her tickets plus $4.50 for a program each game. A second person pays $18.68 for a

ticket to evey game, but doesn't buy programs. In how many games will they have paid the same amount
Mathematics
1 answer:
blsea [12.9K]3 years ago
7 0

Answer:

7 games

Step-by-step explanation:

<u>First Person:</u>

Fixed Cost of 99.26

Variable Cost of 4.50 per game (program cost)

<u>Second Person:</u>

No Fixed Cost

Variable cost of 18.68 per game (ticket cost)

Now, we let the number of games be "x", so we can write 2 equations for each person. Then we equate and find at what number of games, the amount paid by both person would be same. Shown below:

<u>First Person Equation:</u>

99.26 + 4.50x

<u>Second Person Equation:</u>

18.68x

Now, equate and solve for x:

99.26 + 4.50x = 18.68x

99.26 = 18.68x - 4.50x

99.26 = 14.18x

x = 99.26/14.18

x = 7

So, the answer is 7 games

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\huge\bold\green{Answer:-}

Simplifying

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Subproblem 1

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Set the factor '(6c + -7d)' equal to zero and attempt to solve:

Simplifying

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6c + -7d = 0

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<h2>I HOPE IT HELPS ♥️</h2>

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