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natta225 [31]
3 years ago
12

Find the value of the expression

Mathematics
1 answer:
Cloud [144]3 years ago
6 0
The value of expression is 41
You might be interested in
Given that log 2 = 0.3010 and log 3 = 0.4771 , how can we find log 6 ? ​
bearhunter [10]

Answer:

\sf \log_{10}6=0.7781

Step-by-step explanation:

<u>Given</u>:

\sf \log_{10} 2 = 0.3010

\sf \log_{10} 3 = 0.4771

To find log₁₀ 6, first rewrite 6 as 3 · 2:

\sf \implies \log_{10}6=\log_{10}(3 \cdot 2)

\textsf{Apply the log product law}: \quad \log_axy=\log_ax + \log_ay

\implies \sf \log_{10}(3 \cdot 2)=\log_{10}3+\log_{10}2

Substituting the given values for log₁₀ 3 and log₁₀ 2:

\begin{aligned} \sf \implies \log_{10}3+\log_{10}2 & = \sf 0.4771+0.3010\\ & = \sf 0.7781 \end{aligned}

Therefore:

\sf \log_{10}6=0.7781

Learn more about logarithm laws here:

brainly.com/question/27953288

brainly.com/question/27963321

5 0
1 year ago
Read 2 more answers
Please help with this​
Ratling [72]

Answer:

5.5 or simply 6

Step-by-step explanation:

6 = 33

1 = x

6x = 33

x = 5.5 ~6

8 0
3 years ago
Read 2 more answers
Help pls<br> I would use 2 for this right
kipiarov [429]
<h2>Answer:</h2>

Step-by-step explanation:

yeah

8 0
11 months ago
Does 3y-x=6 have a slope of -3
inessss [21]

Answer:

no

Step-by-step explanation:

y=mx+b

applied to the information given:

3y=x+6,

divide both sides by 3

y=1/3x+2

slope is 1/3

8 0
3 years ago
On a test, the marks for ten students are: 2 students, 85%; 4 students, 78%; 3
anzhelika [568]

Answer:

77.2%

Step-by-step explanation:

The average formula is:

Average = \frac{Sum/of/all/numbers}{How/many/numbers/there/are}

Let's first find the sum of all the numbers (remember sum means to add):

(2)(85) + (4)(78) + (3)(66) + 92 = ?

170 + 312 + 198 + 92 = 772

There are marks for 10 students so that is what goes at the bottom (10 students, 10 test scores)

Plug both things into the equation:

Average = \frac{772}{10} \\= 77.2

Therefore, the average mark on the test was 77.2%

<em>Hope this helps!!</em>

<em>- Kay :)</em>

6 0
3 years ago
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