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Vesnalui [34]
2 years ago
12

What's the square root of 628

Mathematics
1 answer:
Galina-37 [17]2 years ago
8 0
4rt33 or 4 times the square root of 33
4 = the square root of sixteen, so the square root of 16 times the square root of 33 = the square root of 628
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Y^3-9y^2+y-9 I don't know how to solve this can you help
aleksley [76]
I'm guessing your problem is this:
y³ - 9y² + y - 9 = 0
right?

In solving this problem, I recommend doing this:
y³ - 9y² + y - 9 = 0
Factor out a y² from the first two numbers in the problem:
y²(y - 9) + (y - 9) = 0
Separate the parentheses which means y - 9 goes on one side. The y² added a one since it came from the + 1 in the middle of expression. When you're separating parentheses like this you just take the outside numbers and combine them together. Since + 1 came from the outside of the (y - 9) and y² also was sitting on the outside of (y - 9) combine them to make y² + 1. Like this:
(y² + 1)(y - 9) = 0
Now separate your two parentheses to two separate problems:
(y² + 1) = 0    and    (y - 9) = 0
Now you're y² + 1 will equal:
y² = -1
y = √-1 <-- This number doesn't exist so it will be an imaginary number (i). If you guys didn't learn that in your class I recommend just leaving it as i for that part.
Now solve y - 9 = 0:
y = 9 <-- Since we added nine to both sides to get this.

So you're final answer should be y = i and 9
3 0
3 years ago
Maya spent her allowance on playing an arcade game a few times and riding the Ferris wheel more than once.
goldfiish [28.3K]
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dybincka [34]

Answer:

Hello! Your answer is less than. (<)

Step-by-step explanation:

I took the test and got it right, proof below!!!!

Hope this helps!! so so sorry if im late! <3

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(13x – 4) + (–6x + 15) =

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