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3 years ago

somebody please help me on this geometry it is urgent!! i’ll mark you the brainliest please don’t waste answers

Mathematics

1 answer:

Elodia [21]3 years ago

5 0

Red angle is 180-48=132
And the third angle inside triangle is 180-62+48=180-110=70

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4 x 4/12= Sheeeeeeeeeeeeeeeesh

Crazy boy [7]

Answer:

1.3 or $\frac{13}{10}$

Hope this helps!

6 0

3 years ago

Read 2 more answers

If y varies directly with x and y = -15 when x = 3, find x when y = 10.

Anika [276]

Answer:

like here x= 3 and y= -15

here, its 5 times goes in negative

now if y = 10 TO X IS 5 TIME POSITIVE HERE = 10×5 = 50

4 0

3 years ago

Use a benchmark to find an equivalent percent for each fraction. 9/10 and 2/5. Please help! :o will mark brainliest if can!

denpristay [2]

Answer

9/10=90% and 2/5=40%

Explanation

9÷10=0.9 0.9x100=90%

2÷5=0.4 0.4x100=40%

hope this helps!

have a wonderful day :)

3 0

3 years ago

Solve the following system of equations by graphing.

never [62]

Answer:

(x,y)=(3,1)

Step-by-step explanation:

8 0

3 years ago

The deck of a bridge is suspended 275 feet above a river. If a pebble falls off the side of the bridge, the height, in feet, of

Ivenika [448]

Answer:

Our equation for the height is:

y(t) = 275 - 16*t^2.

a) To find the average velocity between two times, t1 and t2, (where t2 > t1) the equation is:

$AV = \frac{y(t2) - y(t1)}{t2 - t1}$

Then:

i) t1 = 4s, t2 = 4s + 0.1s = 4.1s

The average velocity is:

$AV = \frac{(275 - 16*4.1^2) - (275 - 16*4^2)}{4.1 - 4} = \frac{16(4^2 - 4.1^2)}{0.1} = -129.6$

And the units will be ft/s, so the average speed is:

-129.6 ft/s

The minus sign is because te pebble is falling down.

ii) t1 = 4s, t2 = 4s + 0.05s = 4.05s

The average velocity is:

$AV = \frac{(275 - 16*4.05^2) - (275 - 16*4^2)}{4.05 - 4} = \frac{16(4^2 - 4.05^2)}{0.05} = -128.8$

So the average speed is -128.9 ft/s

iii) t1 = 4s, t2 = 4s + 0.01s = 4.01s

The average speed is:

$AV = \frac{(275 - 16*4.01^2) - (275 - 16*4^2)}{4.01 - 4} = \frac{16(4^2 - 4.01^2)}{0.01} = -128.16$

The average speed is -128.16 ft/s.

b) The instantaneous velocity of the pebble after 4 seconds can be obtained by looking at the velocity equation, that is the derivative of the height equation.

v(t) = dy(t)/dt.

v(t) = -2*16*t + 0

Then the velocity at t = 4s is:

v(4s) = -32*4 = -128

The instantaneous velocity at t = 4s is -128 ft/s.

3 0

3 years ago