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3 years ago

If a day was a year, how many does it take to make a million years?

Mathematics

2 answers:

shutvik [7]3 years ago

7 0

1,000,000 days, and it’ll take 83,333 and 10 days for a million years in days make a million years

Tasya [4]3 years ago

6 0

It would take 2,740 days to make a million years.

1,000,000 divided by 365.

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When a graph of a cubic polynomial function rises to the left, it falls to the right true or false

serious [3.7K]

That would be true i think

6 0

2 years ago

Tony buys a washing machine

Lorico [155]

Step-by-step explanation:

£480 = 120% (after adding the 20% VAT).

we want to know how much 100% is.

he do we get from 120% to 100% ?

first the formal long way

£480 = 120%

1% = 120%/120 = 480/120 = £4

100% = 1% × 100 = 4×100 = £400

once you understand this mechanism, you can apply the direct shortcut :

£480 / 1.2 = £400

as a multiplication with 100/120 is the same as a division by 120/100, which is 1.2.

and what we did at the beginning in long form was nothing else than

£480 × 100/120 = 480 × 10/12 = 480 × 5/6 = £400

7 0

1 year ago

Read 2 more answers

Expand using the properties and rules for logarithms

malfutka [58]

Consider expression $\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right).$

1. Use property

$\log_a\dfrac{b}{c}=\log_ab-\log_ac.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2.$

2. Use property

$\log_abc=\log_ab+\log_ac.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2.$

3. Use property

$\log_ab^k=k\log_ab.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2.$

4. Use property

$\log_{a^k}b=\dfrac{1}{k}\log_ab.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{2^{-1}}2=\\ \\=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+\log_22=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+1.$

Answer: correct option is B.

7 0

3 years ago

A circle with radius 9 has a sector with a central angle of 120°.

Vitek1552 [10]

120º is 1/3 of a complete revolution of 360º. So the area of this sector should be 1/3 the area of the complete circle.

A circle with radius 9 has area 9^2 π = 81π.

So the sector has area 81π/3.

Put another way: The area A of a circular sector and its central angle θ (in degrees) occur in the same ratio as the area of the entire circle with radius r according to

A / θ º = (π r ^2) / 360º

==> A = π/360 θ r ^2

In this case, r = 9 and θ = 120º, so

A = π/360 * 120 * 81 = 81π/3

8 0

3 years ago

2+x^2=18 Help please

Harlamova29_29 [7]

Answer:

2+x^2=18 = 2+4^2=18

Step-by-step explanation:

Because when you have the ( ^2) then that means your going to multiply a number by the same number and then 4 times 4 equals 16 and you still have the +2 therefore you add that on the 16 and 16+2 equals 18.

3 0

2 years ago