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2 years ago

Prove the following identity : csc4x−cot4x=csc2x+cot2x .

Mathematics

1 answer:

Elina [12.6K]2 years ago

7 0

Answer: See attached image

Step-by-step explanation:

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Find the measures of all four angles if 3·(m∠1+m∠3) = m∠2+m∠4.

mixas84 [53]

Answer:

Step-by-step explanation:

m∠1=m∠3

m∠2=m∠4

3*(m∠1+m∠3)=m∠2+m∠4

3*(m∠1+m∠1)=m∠2+m∠2

3×2 m∠1=2 m∠2

m∠2=3 m∠1

now m∠1+m∠2=180°

m∠1+3 m ∠1=180

4 m∠1=180

m∠1=180/4=45°

m∠3=45°

m∠2=180-m∠1=180-45=135°

m∠4=135°

5 0

3 years ago

5x + 10y > 40

mel-nik [20]

Answer:

x > -2y + 8

Step-by-step explanation:

7 0

3 years ago

2 2 (2,2) 4 2 2 4 x -2 (1,-2)What is the slope

GarryVolchara [31]

Answer:

Step-by-step explanation:

8 0

3 years ago

⎧

d1i1m1o1n [39]

Given:

The given expression to find the nth term of the sequence is $d(n)=d(n-1) \cdot (-5)$

The first term of the sequence is $d(1)=8$

We need to determine the third term of the sequence.

Second term:

The second term of the sequence can be determined by substituting n = 2 in the nth term of the sequence.

Thus, we have;

$d(2)=d(2-1) \cdot (-5)$

$d(2)=d(1) \cdot (-5)$

$d(2)=8 \cdot (-5)$

$d(2)=-40$

Thus, the second term of the sequence is -40.

Third term:

The third term of the sequence can be determined by substituting n = 3 in the nth term of the sequence.

Thus, we have;

$d(3)=d(3-1) \cdot (-5)$

$d(3)=-40 \cdot (-5)$

$d(3)=120$

Thus, the third term of the sequence is 120.

7 0

3 years ago

Read 2 more answers

(9,5) and (4,-7) find the distance between two points

Pani-rosa [81]

Answer:

13 units

Step-by-step explanation:

Use the distance formula, d = $\sqrt{(x2 - x1)^2 + (y2 - y1)^2}$ , where (x2, y2) and (x1, y1) are two different points on the line.

Plug in the values:

d = $\sqrt{(x2 - x1)^2 + (y2 - y1)^2}$

d = $\sqrt{(9 - 4)^2 + (5 + 7)^2}$

d = $\sqrt{5^2 + 12^2}$

d = $\sqrt{25 + 144}$

d = $\sqrt{169}$

d = 13

6 0

3 years ago