I^5 + i^6 + i^7 + i^8
i^11 + i^15
i^26
therefore your answer is:
i^26
Cos ( 390)
- 4 cot (-45)
Csc (60)
Hope this helps
A
evaluate f(5) and f(2)
f(5) = 5m + b and f(2) = 2m + b, hence
f(5) - f(2) = 5m + b - 2m - b = 3m
the expression simplifies to
= 2 ( cross- multiply )
3m = 6 ( divide both sides by 3 )
m = 2 → A
Answer:
point and lines
Step-by-step explanation:
We know that
if the club includes one set of identical
triplets wearing matching clothes
then
the number of different arrangements that are
possible is
10! / 3! = (10*9*8*7*6*5*4*3!)/3!
=604,800
The answer is
<span>604,800</span>
