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castortr0y [4]
3 years ago
7

How do you solve a diagram

Mathematics
1 answer:
Sonja [21]3 years ago
3 0
Read.................
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Precal. Find the sum. Show every step you took to get to your answer. I will give brainliest if you are correct and show all wor
Ymorist [56]

Answer:

I think your forgot to add some parts of this question, because you can't do anything with this except simplify it down a little maybe. But, I will provide the simplified version of this.

\frac{x-4}{x^2-2x}+\frac{4}{x^2-4}

= \frac{x-4}{x\left(x-2\right)}+\frac{4}{x^2-4}

= \frac{x-4}{x\left(x-2\right)}+\frac{4}{\left(x+2\right)\left(x-2\right)}

= \frac{\left(x-4\right)\left(x+2\right)}{x\left(x-2\right)\left(x+2\right)}+\frac{4x}{\left(x+2\right)\left(x-2\right)x}

= \frac{\left(x-4\right)\left(x+2\right)+4x}{x\left(x-2\right)\left(x+2\right)}

= \frac{x+4}{x\left(x+2\right)}

Step-by-step explanation:

Hope this helped!

8 0
3 years ago
I need help in math!!!
PIT_PIT [208]

Answer:

This angle is acute, so it cant be C or D.

Step-by-step explanation:

Imma go with A.

3 0
3 years ago
In slope intercept form what is the equation of the line having a slope of 5 and passing through the point (-6,-26)
____ [38]
Slope/gradient = 5
y= MX + C
(-6,-26)
-6 is x1 and -26 is y1
so therefore y= 5x -26
5 0
3 years ago
Anyone help please!!!!
Andre45 [30]
We are to verify the identity:

cos(α-B)-cos(α+B) = 2 sinα sinβ

Left hand side = cos(α - B)-cos(α + B) 

= cosα cosβ + sinα sinB - (cosα cosB - sinα sinβ)

= cosα cosβ + sinα sinB - cosα cosB + sinα sinβ)

= sinα sinβ + sinα sinβ

= 2 sinα sinβ

= Right Hand side
6 0
3 years ago
Read 2 more answers
BELP ME WITH THIS PLZ!!!!!!
kati45 [8]

Answer:

The entire area of the sailboat is 60cm²

Step-by-step explanation:

You can find the area of this shape by breaking it down into simpler shapes and adding up their individual areas.

In this case, the areas we'll use are the rectangle at the bottom, and the pair of triangles at the top.

Because the two triangles can be put together to form a single triangle, we don't need to measure them independently.  We can simply take the total length of their bases, multiply it by their height, and divide by two.  This follows the rule that the area of a triangle is equal to the area of the square that contains it divided by two.

(2cm + 3cm) × 6cm

= 5cm × 6cm

= 30cm²

The rectangle's area is of course equal to its width times its height, so we can say:

2.5cm × 12cm

= 30cm²

The total area of the shapes then is 30cm² + 30 cm², giving us a total area of 60cm²

3 0
3 years ago
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