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GaryK [48]
3 years ago
11

Can you plz do 6 and 7 and 10 it will be a lot for me

Mathematics
1 answer:
Mila [183]3 years ago
5 0

36 ÷ 4 can be written as:

Thirty-six divided by four.

24 - (6 + 3) can be written as:

The difference of twenty-four and six plus three.

We'll use the expression x - 7 for this one.

The difference between a number and seven.

Hope this helps!


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II. Identify the following terms described in each item. Quantitative & Qualitate. It can be separated into different catego
guajiro [1.7K]

It is a branch of mathematics that deals with the collection, organization presentation, analysis, and interpretation of data.​

1. C. Discrete

2. A. interval

3. B. Quantitative data

4. B. Ratio

5. C. Quantitative

1. A random variable is called discrete if it has either a finite or a countable number of possible values.

A random variable is called continuous if its possible values contain a whole interval of numbers.

2. The third level of measurement is the interval level of measurement. The interval level of measurement not only classifies and orders the measurements but also specifies that the distances between each interval on the scale are equivalent along the scale from low interval to high interval.

3. Quantitative data consist of numerical measurements or counts.

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6 0
1 year ago
Find the directional derivative of f(x,y,z)=z3−x2yf(x,y,z)=z3−x2y at the point (−5,5,2)(−5,5,2) in the direction of the vector v
olga_2 [115]

We are given

f=z^3 -x^2y

Firstly, we can find gradient

so, we will find partial derivatives

f_x=0 -2xy

f_x=-2xy

f_y=0 -x^2

f_y=-x^2

f_z=3z^2

now, we can plug point (-5,5,2)

f_x=-2*-5*5=50

f_y=-(-5)^2=-25

f_z=3(2)^2=12

so, gradient will be

gradf=(50,-25,12)

now, we are given that

it is in direction of v=⟨−3,2,−4⟩

so, we will find it's unit vector

|v|=\sqrt{(-3)^2+(2)^2+(-4)^2}

|v|=\sqrt{29}

now, we can find unit vector

v'=(\frac{-3}{\sqrt{29} } , \frac{2}{\sqrt{29} } , \frac{-4}{\sqrt{29} })

now, we can find dot product to find direction of the vector

dir=(gradf) \cdot (v')

now, we can plug values

dir=(50,-25,12) \cdot (\frac{-3}{\sqrt{29} } , \frac{2}{\sqrt{29} } , \frac{-4}{\sqrt{29} })

dir=(-\frac{150}{\sqrt{29} } - \frac{50}{\sqrt{29} } - \frac{48}{\sqrt{29} })

dir=-\frac{248\sqrt{29}}{29}.............Answer



7 0
3 years ago
Read 2 more answers
The position of an open-water swimmer is shown in the graph. The shortest route to the shoreline is one that is perpendicular to
Stolb23 [73]

Answer:

Step-by-step explanation:

To define the perpendicular line we need to first know the slope of the reference line graphed.

m=(y2-y1)/(x2-x1) we have points (0,5) and (2,1)

m=(1-5)/(2-0)

m=-4/2

m=-2

For lines to be perpendicular their slopes must satisfy

m1m2=-1, we have a line with a slope of -2 so

-2m=-1

m=1/2, so our perpendicular line is so far

y=x/2+b, it must have point (3,2) so we can solve for b

2=3/2+b

b=1/2, so the swimmer will travel along the line

y=x/2+1/2

6 0
3 years ago
What is the answer to -3z > -4.5 ?
Pani-rosa [81]

Answer:

z<1.5

Step-by-step explanation:

3 0
2 years ago
Bobby is 12 years old. His age is nine
KatRina [158]

Answer:

65 because 12 plus 9 is 21 then 3 times 21 is 65

4 0
2 years ago
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