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3 years ago

9

Mathematics

2 answers:

Ymorist [56]3 years ago

6 0

A. 12 dollars. 84 /7=12

velikii [3]3 years ago

5 0

Divide 84 by 7 and you will get 12

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Can someone tell me what the lcd is??

Ugo [173]

I think it’s International Classification of Diseases but I’m not sure cause it doesn’t match anything with math good luck though.

7 0

2 years ago

Anyone know the answer?

ANTONII [103]

PKE is a triangle and its interior angles therefor sum to 180deg:

$P+K+E=180$
$90+(x+6)+2x=180$
$96+3x=180$
$3x=84$
$x=\frac{84}{3}=28deg$

5 0

3 years ago

find the probability of picking a red marble and a green marble when 2 marbles are picked (without replacement)from a bag contai

mina [271]

Answer:

p = 6/11.

Step-by-step explanation:

So we have a bag that contains 6 red marbles and 6 green marbles.

Then the total number of marbles that are in that bag is:

6 + 6 = 12

There are 12 marbles in the bag, and we assume that all marbles have the same probability of being randomly drawn.

Now we draw two marbles, we want to find the probability that one is red and the other is green.

The first marble that we draw does not matter, as we just want the second marble to be of the other color.

So, suppose we draw a green one in the first attempt.

Then in the second draw, we need to get a red one.

The probability of drawing a red one will be equal to the quotient between the red marbles in the bag (6) and the total number of marbles in the bag (12 - 1 = 11, because one green marble was drawn already)

Then the probability is:

p = 6/11.

Notice that would be the exact same case if the first marble was red.

Then we can conclude that the probability of getting two marbles of different colors is:

p = 6/11.

6 0

2 years ago

According to a 2009 Reader's Digest article, people throw away about 14% of what they buy at the grocery store. Assume this is t

ahrayia [7]

Answer:

18.67% probability that the sample proportion does not exceed 0.1

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

For the sampling distribution of a sample proportion, we have that $\mu = p, \sigma = \sqrt{\frac{p(1-p)}{n}}$