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murzikaleks [220]
3 years ago
14

El gerente de una cafeteria decide experimentar con

Mathematics
1 answer:
vagabundo [1.1K]3 years ago
3 0

Answer:

I dont undersatnd

Step-by-step explanation:

20 x 20 x 20 x 020

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X=5y+41<br> X+3y=-15<br> Substitution method
inn [45]

you substitute 5y+41 for x and get 5y+41+3y=-15 then you simplify by doing 8y+41=-51 subtract 41 from each side and divide by 8 to get y alone. That's how you get 11.5 for your answer.
3 0
3 years ago
Read 2 more answers
A telephone pole has a wire attached to its top that is anchored to the ground. The distance from the bottom of the pole to the
Flauer [41]

Answer:

Height is 135 ft

Step-by-step explanation:

Notice that wire, pole, and ground form a right angle triangle, for which we name h = height of the pole one of the legs (the horizontal leg) is h - 51. The wire (which is the hypotenuse of the right angle triangle is: h + 24.

Then we can use the Pythagorean theorem to solve for the height (h):

h^2 + (h - 51)^2 = (h + 24)^2

h^2 + h^2 -102 h + 2601 = h^2 + 48 h + 576

grouping all terms on the left of the equal sign, we get:

h^2 -150 h + 2025 = 0

This gives two possible answers:

h = 135

and

h = 15

We opt for h = 135, because the other solution will render a negative leg for the triangle.

7 0
3 years ago
Kathy runs a 26.2- mile marathon at an average pace of 6.2 minutes per mile how long will it take her to finish
mojhsa [17]
So the simplest way to think of this is that if 1 mile takes 6.2 minutes, 26.2 miles can be multiplied by 6.2 to find the total time. <span />
6 0
4 years ago
What is -3 1/6+5 3/5<br> help me please and thank you
balandron [24]
The answer should be 2 13/30.
6 0
3 years ago
A certain class has 20 students, and meets on Mondays and Wednesdays in a classroom with exactly 20 seats. In a certain week, ev
Olin [163]

Answer:

The probability that no one sits in the same seat on both days of that week is given by, P(\cap^{20}_{i=1}A_i^c)=\frac{1}{e}

Step-by-step explanation:

Given : A certain class has 20 students, and meets on Mondays and Wednesdays in a classroom with exactly 20 seats. In a certain week, everyone in the class attend both days. On both days, the students choose their seats completely randomly (with one student per seat).

To find : The probability that no one sits in the same seat on both days of that week ?

Solution :

Let A_i be the i-th student sits on seat which he has been sitting on Monday.

According to question,

We have to calculate P(\cap^{20}_{i=1}A_i^c)

Applying inclusion exclusion formula,

P(\cap^{20}_{i=1}A_i^c)=1-P(\cap^{4}_{i=1}A_i)

P(\cap^{20}_{i=1}A_i^c)=1-P(A_1)+...+P(A_{20})-P(A_1\cap A_2)+...+P(A_{19}\cap A_{20})+P(A_1\cap A_2\cap A_3)+...+P(A_{18}\cap A_{19}\cap A_{20})....-P(A_1\cap A_2...\cap A_{20})

Using symmetry,

P(\cap^{20}_{i=1}A_i^c)=1-\sum^{20}_{k=1}(-1)^{k+1}\binom{20}{k}P(A_1\cap ...\cap A_k)

P(\cap^{20}_{i=1}A_i^c)=1-\sum^{20}_{k=1}(-1)^{k+1}\binom{20}{k}\frac{(20-k)!}{20!}

P(\cap^{20}_{i=1}A_i^c)=1+\sum^{20}_{k=1}(-1)^{k}\frac{1}{k!}

P(\cap^{20}_{i=1}A_i^c)=\sum^{20}_{k=0}(-1)^{k}\frac{1}{k!}

P(\cap^{20}_{i=1}A_i^c)=\frac{1}{e}

Therefore, The probability that no one sits in the same seat on both days of that week is given by, P(\cap^{20}_{i=1}A_i^c)=\frac{1}{e}

8 0
3 years ago
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