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r-ruslan [8.4K]
2 years ago
5

(Essential Question) How do you create equations and use them to solve problems?

Mathematics
1 answer:
scZoUnD [109]2 years ago
5 0

Answer:

Step-by-step explanation:

equations are created to solve for a certain variable. you can use the data given in the word problem to formulate a valid equation that incorporates all important components of the word problem. the variable can be represented as any letter (most commonly x or y) to find a value that is inconsistent or unknown. this is helpful to find a certain thing in the problem, such as the amount of hours needed to earn a certain amount of money.

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Jody practiced a piano piece for 500 seconds bill practiced a piano piece for 8 minutes who practiced longer explain
Mrac [35]

Answer:

Jody

Step-by-step explanation:

You can either convert 500 seconds to minutes or 8 minutes to seconds to compare. I'll do both.

There is 60 seconds in a minute. To find the total minutes of 500 seconds, divide 500 by 60 → 8.3, which means that Jody practiced for 8.3 minutes.

To find the total seconds of 8 minutes, multiply 60 seconds per minute by 8 minutes → 60 * 8 = 480 seconds which means that Bill practiced for 480 seconds.

Now you can compare. Jody practiced for 500 seconds, or 8.3 minutes. Bill practiced for 480 seconds, or 8 minutes. Jody practiced longer.

7 0
2 years ago
Which is the graph of r = 6 cos?
Alex777 [14]

Answer:

Using the formula

r

=a

cos

(

θ

)

or

r

=

a

sin

(

θ

), graph the circle.

r

=

6

cos

(

θ

)

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
A psychologist would like to examine the effect of fatigue on mental alertness. An attention test is prepared which requires sub
lianna [129]

Answer:

The calculated value of t= 0.1908 does not lie in the critical region t= 1.77 Therefore we accept our null hypothesis that  fatigue does not significantly increase errors on an attention task at 0.05 significance level

Step-by-step explanation:

We formulate null and alternate hypotheses are

H0 : u1 < u2 against Ha: u1 ≥ u 2

Where u1 is the group tested after they were awake for 24 hours.

The Significance level alpha is chosen to be ∝ = 0.05

The critical region t ≥ t (0.05, 13) = 1.77

Degrees of freedom is calculated df = υ= n1+n2- 2= 5+10-2= 13

Here the difference between the sample means is x`1- x`2= 35-24= 11

The pooled estimate for the common variance σ² is

Sp² = 1/n1+n2 -2 [ ∑ (x1i - x1`)² + ∑ (x2j - x`2)²]

= 1/13 [ 120²+360²]

Sp = 105.25

The test statistic is

t = (x`1- x` ) /. Sp √1/n1 + 1/n2

t=   11/ 105.25 √1/5+ 1/10

t=  11/57.65

t= 0.1908

The calculated value of t= 0.1908 does not lie in the critical region t= 1.77 Therefore we accept our null hypothesis that  fatigue does not significantly increase errors on an attention task at 0.05 significance level

5 0
3 years ago
If rectangle A has a length and width that are z times the length and width of rectangle B, which of the following is true?
coldgirl [10]
The answer is A the perimeter of rectangle A is z times the perimeter of rectangle B
6 0
3 years ago
Scott bought a pen and received change of $4.75 in 25 coins, all dimes and quarters. How many of each kind did he receive?
dangina [55]

Answer:

He received 10 dimes and 15 quarters.

Step-by-step explanation:

Dimes = $0.10

Quarters = $0.25

Variable x = dimes

Variable y = quarters

Create a pair of linear equations:

0.10x + 0.25y = 4.75

x + y = 25

Isolate any variable, using an equation of your choice:

x + y = 25

x = 25 - y

Plug in this new value of x into the other equation:

0.10(25 - y) + 0.25y = 4.75

Use the distributive property:

2.5 - 0.10y + 0.25y = 4.75

Combine like terms:

2.5 + 0.15y = 4.75

Isolate variable y:

0.15y = 2.25

y = 15

Plug in the value of y into any equation:

x + y = 25

x + 15 = 25

Isolate variable x:

x = 10

7 0
2 years ago
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