If
is the variable of the horizontal axis, then you can solve for
to get the equation of the line in slope-intercept form in the
plane:
i.e. a line with slope
through the origin, which means it is contained in the first and third quadrants. Since the terminal side of
has a negative sine, the angle must lie in the third quadrant.
Because the slope of the line is
, you can choose any length along the line to make up the hypotenuse of a right triangle with reference angle
. Any such right triangle will have
, regardless of whether the angle is the first or third quadrant. But since
is known to lie in the third quadrant, and so
and
are both negative, you have
Answer:
The relationship between the graphs is the intersection point at (0.667,1.333)
Step-by-step explanation:
we have
y=2x ----> equation A
The slope of the line A is equal to m=2
The line passes through the origin
y=2-x ----> equation B
The slope of the line B is m=-1
The x-intercept is the point (2,0)
The y-intercept is the point (0,2)
Line A and Line B are not parallel (the slopes are not equal)
Line A and Line B are not perpendicular (the product of their slopes is not equal to -1)
so
The relationship between Line A and Line B is the intersection point both graphs
using a graphing tool
The intersection point is (0.667,1.333)
see the attached figure
The intersection point is a common point , therefore belongs to both lines
Step-by-step explanation:
I think we have to find the factors so
3x2 + 42x + 105
First we will multiply 105 by 3 = 315 then find factors of 315 which may add or subtract = 42
So 45 and 7
3x2 + 45x - 7x + 105
3x( x + 15) - 7(x - 15)
(3x - 7) and ( x - 15) are the factors
There is a problem please recheck the question
Answer:
3kh - 12.4h
Step-by-step explanation:
h(3k-12.4)
= h(3k) - h(12.4)
= 3kh - 12.4h
