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DerKrebs [107]
2 years ago
8

Find the width (w)of a rectangular room with a length (l) of 60 meters and an area (a) of 2,400 square meters

Mathematics
1 answer:
sdas [7]2 years ago
6 0

Answer:

The width of the room would be 40 meters

Step-by-step explanation:

To find this, start with the area formula.

A = LW

Now input the known length and area.

2400 = 60W

Now divide both sides by 60

40 = W

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If f(x) = 6x +5 and g(x) = 2x – 7 find (fºg)(x)
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Answer:

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Step-by-step explanation:

Step 1: Define

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Step 2: Find f(g(x))

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22. Mona is in her garden jumping on stones (as shown below).
iris [78.8K]

\large\green{\sf\boxed{Given:-}}

<u>Mona starts from 68th stone</u>

<u>She jumps</u><u> </u><u>23</u><u> </u><u>stones</u><u> </u><u>ahead</u><u> </u>

<u>Then</u><u> </u><u>she</u><u> </u><u>jumps</u><u> </u><u>28</u><u> </u><u>stones</u><u> </u><u>back</u>

\large\red{\sf\boxed{To \:find:-}}

<em>Her final position=?</em>

\large{|\underline{\mathtt{\red{S}\blue{o}\orange{l}\pink{u}\blue{t}\purple{i}\green{o}\red{n}\blue{:}\orange{-}}}}

  • Add 23 in 68 [Given]

\begin{gathered}\\ \sf\longmapsto 68+23=91\end{gathered}

  • Subtract 28 from 91

\begin{gathered}\\ \sf\longmapsto 91-28=Her\:final\:position\end{gathered}

\begin{gathered}\\ \sf\longmapsto =63\end{gathered}

  • To find how much stones she is ahead or back we will Subtract 63 from 68 which was her initial position.

\begin{gathered}\\ \sf\longmapsto 68-63=5\end{gathered}

So, Mona will be <em><u>5</u></em><em><u> </u></em><em><u>stones</u></em><em><u> </u></em><em><u>behind</u></em><em><u> </u></em><em><u>from</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>starting</u></em><em><u> </u></em><em><u>stone</u></em><em><u>.</u></em>

☯️Hence, Option C is correct

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