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Marina CMI [18]

3 years ago

15

Assume yo make $10 an hour and work 20 hours a week. In addition you receive $1,200 a year in income from a trust fund . What is

your total annual income?

1 answer:

Lisa [10]3 years ago

6 0

Life life life man woman child
Stop making jokes about this life
Said a person with a hat

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The school buses at a middle school each hold 38 students. The school has, b, buses.

mel-nik [20]

Answer:

38bs

Step-by-step explanation:

multiply the number of students that each bus can hold by the no of buses 38s×b=38bs

8 0

3 years ago

The cost to rent a surfboard at the beach is $10.25 an hour plus an insurance fee of $25. Keith spent $55.75 when renting a surf

goblinko [34]

Answer: Keith spent 3 hours renting the surfboard.

Step-by-step explanation:

h=hour

10.25h+25=55.75

55.75-25= 30.75

30.75/10.25= 3

and if you want to check you can do

10.25(3)+25=

which would equal to 55.75

4 0

2 years ago

The volume of the right triangular prism is 91.8ft. The height of the prism is 10.8ft. What is the area of each base? Show your

kaheart [24]

Answer:

8.5 ft.

Step-by-step explanation:

We'll use this right triangular prism volume formula: base area x height = volume

base area = ?

length = 10.8

volume = 91.8

base area x 10.8 = 91.8

Divide both sides by 10.8

base area x 10.8/10.8 = 91.8/10.8

base area = 8.5

4 0

2 years ago

What is the domain of f

frez [133]

Answer:

[ - 6 , 6 ]

Step-by-step explanation:

This is because the value of f(t) for x values only ranges from -6 to 6.

Please mark for Brainliest!! :D Thanks!!

For more questions or more information, please comment below!

8 0

3 years ago

Whats the intrgral of <img src="https://tex.z-dn.net/?f=%20%5Cint%20%20%5Cfrac%7Bx%5E2%2Bx-3%7D%7B%28x%5E3%2Bx%5E2-4x-4%29%5E2%7

rosijanka [135]

$\displaystyle\int\frac{x^2+x-3}{(x^3+x^2-4x-4)^2}\,\mathrm dx$

Notice that $x^3+x^2-4x-4=x^2(x+1)-4(x+1)=(x-2)(x+2)(x+1)$ . Decompose the integrand into partial fractions:

$\dfrac{x^2+x-3}{(x-2)^2(x+2)^2(x+1)^2}$
$=\dfrac1{3(x+1)}-\dfrac{11}{32(x+2)}-\dfrac1{3(x+1)^2}-\dfrac1{16(x+2)^2}+\dfrac1{96(x-2)}+\dfrac1{48(x-2)^2}$

Integrating term-by-term, you get

$\displaystyle\int\frac{x^2+x-3}{(x^3+x^2-4x-4)^2}\,\mathrm dx$
$=-\dfrac1{48(x-2)}+\dfrac1{3(x+1)}+\dfrac1{16(x+2)}+\dfrac1{96}\ln|x-2|+\dfrac13\ln|x+1|-\dfrac{11}{32}\ln|x+2|+C$

5 0

3 years ago