Completed question:
In the game of tic-tac-toe, if all moves are performed randomly the probability that the game will end in a draw is 0.127. Suppose six random games of tic-tac-toe are played. What is the probability that at least one of them will end in a draw?
Answer:
0.557
Step-by-step explanation:
For each game, the probability of not end in a draw is 1 - 0.127 = 0.873. Thus, because each game is independent of each other, the probability of all of them not end in a draw is the multiplication of the probability of each one:
0.873x0.873x0.873x...x0.873 = 0.873⁶ = 0.443
Thus, the probability that at least one of them end in a draw is the total probability (1) less the probability that none of them en in a draw:
1 - 0.443
0.557
70(0.21) + 99(0.23) + 91(0.23) + 90(0.33)
= 14.7 + 22.77 + 20.93 + 29.7
= 88.1%
1/5^2 = 1/25
1/5^1 = 1/5
1/5^0 = 1
1/5^-1 = 5
1/5^-2 = 25
Answer:
cheryl
Step-by-step explanation:
Answer:
12?
Step-by-step explanation:
i might be wrong, but from what it looks like, it shows 3 sections and one is labeled 4.
