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Elanso [62]
2 years ago
11

System of Equations y=-x-1 y+x=3 Solve?

Mathematics
1 answer:
ozzi2 years ago
6 0
Solve by substitution

\sf{y=-x-1}
\sf{y+x=3}

Just plug in y=-x-1 into y+x=3

So we get:

\sf{(-x-1)+x=3}

Simplify that:

\sf{-1=3}

And since that is not true, that means this system of equations has no solutions!
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Y∝1√x<br> If <br> y=7 when x=64<br> find, <br> x when y=8
Taya2010 [7]

Answer:

uhm im really sorry about this but i really need points i would help but id get it wrong im bad aat math

Step-by-step explanation:

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2 years ago
Suppose that the local sales tax rate is 5 %
bazaltina [42]

Answer:

A: Tax paid us $1370

B: Total cost= car cost + taxes

$27,400+ $1370

=$28,770

Step-by-step explanation:

4 0
2 years ago
sarah uses 2/3 of her supply of cheese to make pizza and 1/9 of her supply of cheese to make lasagna. If Sarah uses 2 1/3 pounds
Oksana_A [137]

Answer: 0.05 cup

Step-by-step explanation:

Divide 2.5 by 10 to find how much is in one of Sarah’s dishes.

This gives you 0.25

Divide 1.6 by 8 to find how much is in one of Amy's dishes.

This gives you 0.2

Now minus 0.2 from 0.25.

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hope this helps

4 0
2 years ago
Plzzzz help I REALLY NEED HELP
VashaNatasha [74]

Answer:

1/9

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
The water level, measured in feet above mean sea level, of Lake Lanier in Georgia, USA, during 2012 can be modeled by the functi
FrozenT [24]

Answer:

May 4th, 2012.

Step-by-step explanation:

The highest level can be found with the help of the First Derivative and Second Derivative Tests. First and second derivatives of the function are, respectively:

l'(t) = 0.04323\cdot t^{2}-0.8354\cdot t +2.703

l''(t) = 0.08646\cdot t - 0.8354

The First Derivative Tests consists on equalizing the first derivative to zero and finding the critical points.

0.04323\cdot t^{2}-0.8354\cdot t +2.703 = 0

Roots are t_{1} \approx 15.672 and t_{2} \approx 4.077. just the second root offer a realistic solution and is test by the second derivative.

l''(4.077) = -0.482 (which leads to a maximum).

Given that a year has 365 days or 12 months, the highest water level occurs at day:

n = \frac{4.077}{12} \cdot (365\,days)

n \approx 124 (May 4th).

5 0
3 years ago
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