$e\cdot e^x -e^{-2}=-2$
$\implies e^{x+1}=e^{-2}-2$
note that RHS is negative. (because e with negative exponent is less than 1)
and LHS is always positive.
so there cannot be any solution
Answer:
150
Step-by-step explanation:
Multiply 3 x 5 x 10
Answer:
$80
Step-by-step explanation:
$5 per hour, then for 16houurs. 5*16=80