Answer:the horizontal displacement is 34.64 meters
The maximum height is 15 meters
Step-by-step explanation:
As the ball moves from the ground at 30 degrees, it travels through a parabolic path. It can therefore be likened to a projectile. The horizontal displacement to where it lands is the range. The formula for determining range,R is
R = U^2Sin2#)/g
Where
U represents the initial velocity of the ball
g is acceleration due to gravity
# represents the angle above the horizontal.
From the information given
# = 30 degrees
U = 20 m/s
g = 10m/s^2
R = 20^2Sin2×30)/10 = (400Sin60)/20 = (400×0.8660)/10
= 34.64 meters
To determine the maximum height of the ball, H,
H = (U^2Sin^2#)/2g
H = (20^2 × Sin^2 30)/2×10
H = (400 × 0.866^2)/20 = 15 meters
<span>6.8 x 10^-2
The scientific notation of 70, 030, 000. To find the scientific notation of this value </span><span><span>
1. </span>We first move the period which separates the whole number from the decimal number which is located after the numbers of the given value.</span>
<span><span>2. </span>We move it in the very recent order number which is seventy million, seven and zero.</span> <span><span>
3. </span>It becomes 7.003</span>
<span><span>4. </span>Thus we count how many moves we did from the tens to the ten million order place.</span> <span><span>
5. </span>7.003 x 10^7<span>
</span></span>
Answer:
2 is the number because half of 5 is 2.5
Answer is 800. Mark as branliest tq
